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Juliette [100K]

3 years ago

8

A rectangular garden measures 25ft by 30ft . Surrounding (and bordering) the garden is a path 2ft wide. Find the area of this pa

th. Be sure to include the correct unit in your answer.

1 answer:

Vaselesa [24]3 years ago

4 0

The answer is circled in yellow.

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Assume that by continuing your education, you increased your yearly earning potential from $21,484 to $39,746. If the additional

Ede4ka [16]

Answer:

By continuing my education I increased my earning potential from $21,484 to $39,746 a year. That's a difference of $18262 a year.

If the additional education costs $18,000, then in one year it will pay for itself.

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Which one of these polls is the correct answer? Please help.

professor190 [17]

M= 4

Hope that helps have a great day!

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3 years ago

Please solve i will give brainiest 100 point question ****** do the whole page please need to pass or i will fail its my final t

dmitriy555 [2]

Answer:

1. Find the difference between the areas.

<u>Area of the small rectangle</u>: $(x+2)(x+7)=x^2+7x+2x+14=x^2+9x+14$

<u>Area of the big rectangle</u>: $(x+9)(x+11)=x^2+11x+9x+99=x^2+20x+99$

The difference is: $11x+85$

$( x^2+20x+99)- (x^2+9x+14)=x^2+20x+99-x^2-9x-14=11x+85$

2.

You can solve this question just by looking at the graph.

a) The height is 4 meters.

$f(d)=h=-2d^2+7d+4$

To find the height of the bleachers, we should consider the moment before the shoot, when the distance is equal to 0.

$f(0)=h=-2(0)^2+7(0)+4$

$h=4$

The height is 4 meters.

b) 9 meters.

For $d=1$

$f(1)=h=-2(1)^2+7(1)+4$

$f(1)=h=-2+7+4$

$h=9$

b) The ball travels 4 meters.

But to calculate it, it is when $h=0$

$0=-2d^2+7d+4$

Using the quadratic formula:

$d=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$d=\frac{-7 \pm \sqrt{7^2-4\left(-2\right)4}}{2\left(-2\right)}$

$d=\frac{-7\pm\sqrt{81}}{-4}$

$d=\frac{-7\pm9}{-4}$

It will give us to solutions, once it is a quadratic equation, but we are talking about a positive distance.

$d=-\frac{1}{2} \text{ or }d=4$

3.

In this question, we have to find the area of the cylinder and the sphere.

From the information given, we have

a = 5mm and d = 5mm, therefore the radius is 2.5 mm.

The volume of a cylinder:

$V=\pi r^2h$

$V=\pi (2.5)^2 \cdot 5$

$V=31.25 \pi$

$V_{c} \approx 98.17 \text{ m}^3$

The volume of the sphere:

$V=\frac{4}{3} \pi r^2$

$V_{s} \approx 65.4 \text{ m}^3$

The volume of the capsule is approximately $163.57 \text{ m}^3$

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3 years ago

Santana had a goal to read 50 pages of his

DIA [1.3K]

He read 110 pages i think

5 0

3 years ago

What is the degree of the polynomial below? 4x^3+3x^2+6x+5<br><br> A. 0<br> B. 3<br> C. 1<br> D. 2

alexira [117]

Answer:

B. 3

Step-by-step explanation:

The degree of this polynomial is based on the highest power on the exponents (if there is more than one variable, it is based on the sum)

The highest power is 3, so the degree is 3

6 0

3 years ago

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