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solniwko [45]
3 years ago
13

In a 10 m2 ecosystem, there are 20 raccoons. The population density of raccoons is _____.

Mathematics
2 answers:
katrin2010 [14]3 years ago
8 0
To find the density of racon all you have to do is to divide number of racoons with surface area because as name says you need to get x number of racoons per m^2

its own name tells you what you need to divide with what.

answer is:
20/10 = 2 raccoons per m^2
crimeas [40]3 years ago
4 0

Answer:

20/10 = 2 raccoons per m^2

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Find the probability. Round your answer to the nearest hundredth, if needed.
padilas [110]

Answer:

0.2

Step-by-step explanation:

Given:

Total number of students = 20

Number of students who have brown hair = 12

Number of students who have blonde hair = 4

Number of students who have red hair = 3

Number of students who have black hair = 1

To find:

Probability of randomly selecting a blonde-haired student from the classroom.

Solution:

Probability refers to chances of occurring of some event.

Probability = Number of favourable outcomes/ Total number of outcomes

Number of favourable outcomes ( Number of students who have blonde hair ) = 4

Total number of outcomes = 20

So,

Probability of randomly selecting a blonde haired student from the classroom = \frac{4}{20}=\frac{1}{5}=0.2

5 0
3 years ago
Have Retirement Benefits
charle [14.2K]

Answer:

(a) The probability of the intersection of events "man" and "yes" is 0.55.

(b) The probability of the intersection of events "no" and "man" is 0.10.

(c) The probability of the union of events "woman" or "no" is 0.45.

Step-by-step explanation:

The information provided is:

             Yes    No   Total

Men       275   50     325

Women  150   25      175

Total      425   75      500

(a)

Compute the probability that a randomly selected employee is a man and a has retirement benefits as follows:

P(M\cap Y)=\frac{n(M\cap Y)}{N}=\frac{275}{500}=0.55

Thus, the probability of the intersection of events "man" and "yes" is 0.55.

(b)

Compute the probability that a randomly selected employee does not have retirement benefits and is a man as follows:

P(N\cap M)=\frac{n(N\cap M)}{N}=\frac{50}{500}=0.10

Thus, the probability of the intersection of events "no" and "man" is 0.10.

(c)

Compute the probability that a randomly selected employee is a woman or has no retirement benefits as follows:

P(W\cup N)=P(W)+P(N)-P(W\cap N)=\frac{175}{500}+\frac{75}{500}-\frac{25}{500}=0.45

Thus, the probability of the union of events "woman" or "no" is 0.45.

5 0
3 years ago
A media company wants to track the results of his new marketing plan so the video production manager recorded the number of use
konstantin123 [22]

Answer:

f(x)=5120(5)^{x}

Step-by-step explanation:

From the image, f(x) and x are rlated by

f(x)=a( {b})^{x}

where b is the common ratio

We first find the value for b

\frac{6400}{5120}= 5

\frac{8000}{6400}= 5

\frac{10000}{8000} = 5

\frac{12500}{10000} = 5

\frac{15625}{12500}=5

so we can say the common ratio, b=5

we put in any value of f(x) and the corresponding value for x to find a value

Let put x=0 and f(x)=5120

This implies that

5120 = a(5)^{0}

but

5^{0} = 1

Hence a=5120

Thus the equation which model the relationship between the weeks and the viewers is

f(x)=5120(5)^{x}

6 0
3 years ago
Six friends share three oatmeal squares equally how much of an oatmeal square does each friend get
Sveta_85 [38]

Each friend gets half of a oatmeal square


Step-by-step explanation:


8 0
3 years ago
Why are there two solutions for the equation |6 + y| = 2? Explain.
Luba_88 [7]
Since it is in absolute value it switches the negative to a positive so here let me show you

|6+y| = 2

If you try -4 you get 2 in a positive form so -4 is one correct.

The second correct one is -8 because 6-8 is -2 but as I was saying before how the absolute value changes it into positive, that means -2 would be switched to 2 meaning that -8 is also a correct answer.

If you need more help just search up what absolute value is.

If you found my answer helpful pls mark has brainliest
3 0
3 years ago
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