In each table, x increases by 1. We start with x = 0 and stop with x = 3. So we will focus on the y columns of each table as those are different.
Let's move from left to right along the four tables.
For the first table, we go from y = 1 to y = 2. That's an increase of 1
Sticking with the first table, we go from y = 2 to y = 4. The increase is now 2
Since the increase is not the same, this means the table is not linear. The y increase must be constant. We can rule out choice A
Choice B can be ruled out as well. Why? Because...
the jump from y = 0 to y = 1 is +1
the jump from y = 1 to y = 3 is +2
The same problem comes up as it did with choice A
Choice C has the same problem, but the increase turns into a decrease half the time. We go from y = 0 to y = 1, then we go back to y = 0 so the "increase" is really a decrease. We can think of it as a negative increase. Regardless, this allows us to rule out choice C
Only choice D is the answer. Each time x goes up by 1, y goes up by 2. Therefore the slope is 2/1 = 2
as the function is polynomial domain exist for all real number ie (-infinity to + infinity) but range exist (0 to +infinity ) due to modulus negetive range do not exist
Answer:
35000
Step-by-step explanation:
The best way to five students from a list of 626 students available such that it exhibits a random process is to List each name on a separate piece of paper; place them all in a hat, and pick five.
The selection process which should be undertaken by the student government, should be one which is inclusive and representative. Hence, the five students to be selected which makes up the sample of the total student should be chosen at random and transparently.
Hence, listing the names of each student on a Seperate piece of paper, placing it in a hat and making 5 selections showcase randomness and transparency, hence, it should be the adopted selection process.
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