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SpyIntel [72]
3 years ago
5

Does anyone know how to simplify this?

Mathematics
2 answers:
yan [13]3 years ago
6 0
The final answer is -5.28825

Papessa [141]3 years ago
3 0
3 × √9 is the same as 3 × 3, which is 9.

Hence, you get -11/9.
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1st Step: 3 - 4x - 7 = -24<br> 2nd Step: 3- 7 - 4x = -24<br> What property justifies the 2nd step
gizmo_the_mogwai [7]

Answer:

the subtraction

Step-by-step explanation:

3 0
2 years ago
Need help with number 22-23. Math hw
Rasek [7]
22. $31.25 divided by 25 = $1.25 for each ticket.

23. $1.50 times 5 = $7.50 to climb the rock wall. 
4 0
2 years ago
Jacks basketball team went to the movies. Adults were $12.00. 5 adults and 12 players came. The total was $120. What was the cos
avanturin [10]
5 dollars is the answer
5 0
2 years ago
Read 2 more answers
Hannah has information about an object in circular orbit around Earth. MEarth = 6. 0 × 1024 kg G = 6. 67 × 10–11 StartFraction m
castortr0y [4]

In order to calculate the tangential speed of the orbiting object   Hannah need the distance of the orbiting object to Earth.

<h3>What is the tangential speed of the object?</h3>

The tangential speed of an object is the linear component of the speed, which is moving in a circular path.

In terms of  the gravitation constant, the tangential speed can be given as,

v=\sqrt{\dfrac{Gm}{r}}

Here, {<em>G</em>} is the gravitation constant, (<em>m</em>) is the mass and (<em>r</em>) is the radius.

Hannah has information about an object in circular orbit around Earth.

The mass of the earth is.

m_E=6. 0 \times10^{24} kg

The value of gravitational constant is,

G=6. 67\times 10{-11}\rm Nm^2/kg^2

The radius of the earth is,

r_E=6. 0 \times 10^6 \rm m

Here, only the distance of the orbiting object to Earth is need to find the tangential speed of the object.

Hence, in order to calculate the tangential speed of the orbiting object   Hannah need the distance of the orbiting object to Earth.

Learn more about the tangential speed here;

brainly.com/question/4933588

7 0
2 years ago
A bird is sitting on a train A moving at a speed of 40 kmph. It sees another train B at a Distance of 200 ms with Speed of 60 km
Aloiza [94]
Solution:

Two trains are moving in opposite direction with Speed 40 kmph and 60 kmph. Make train B stationary and then take the Speed of train A relative to the train B. So relative Speed of train A = 40 + 60 = 100 kmph. Before it crashes into the stationary train B it has to travel a Distance of 200 m which it will do in (0.2/100 ) hours. During this duration, the average Speed of bird has been 10 kmph i.e. before the crash total Distance covered by the bird = 0.2 * 10/100 km = 20 meters.
Hope it helps
7 0
2 years ago
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