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Vaselesa [24]
3 years ago
6

heba ate 1/12 of a box of cereal now the box is 3/4 full what fraction of a full box was there before heba ate it

Mathematics
2 answers:
abruzzese [7]3 years ago
7 0

Now box is 3/4 full


3/4 = 3/4*1


3/4 = 3/4 * 3/3 = 9/12


Box is 9/12 full after heba ate 1/12 of a box of cereal


Initial fraction will be 9/12+1/12


=10/12= 5/6

Leya [2.2K]3 years ago
5 0

Answer:

5/6.

Step-by-step explanation:

If Heba ate 1/12 of a box of cereal and the box is now 3/4 full, then before she ate the box is 3/4 plus the 1/12 (because, in the "before" situation she hasn't eaten yet). So, we need to add the "now" quantity and the quantity eaten:

\frac{3}{4}+\frac{1}{12} = \frac{10}{12} = \frac{5}{6}.

Then, before she ate the cereal, the box is 5/6 full.

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3 years ago
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Which of the following is an equivalent equation obtained by completing the square of the expression below? x^2+6x−8=0 A (x+3)^2
valentina_108 [34]

Answer:

Solving the equation x^2+6x-8=0 by completing the square method we get \mathbf{(x+3)^2=17}

Option B is correct option.

Step-by-step explanation:

We need to solve the equation x^2+6x-8=0 by completing the square method.

For completing the square method: we need to follow: a^2+2ab+b^2=(a+b)^2

We are given:

x^2+6x-8=0

Solving by completing the square

x^2+2(x)(?)+(?)^2-8=0

We need to find ? in our case ? is 3 because 2*3= 6 and our middle term is 6x i,e 2(x)(3)=6x.

So, adding and subtracting (3)^2

x^2+2(x)(3)+(3)^2-8-(3)^2=0\\(x+3)^2-8-9=0\\(x+3)^2-17=0\\(x+3)^2=17

So, solving the equation x^2+6x-8=0 by completing the square method we get \mathbf{(x+3)^2=17}

Option B is correct option.

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3 years ago
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