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Vaselesa [24]
3 years ago
6

heba ate 1/12 of a box of cereal now the box is 3/4 full what fraction of a full box was there before heba ate it

Mathematics
2 answers:
abruzzese [7]3 years ago
7 0

Now box is 3/4 full


3/4 = 3/4*1


3/4 = 3/4 * 3/3 = 9/12


Box is 9/12 full after heba ate 1/12 of a box of cereal


Initial fraction will be 9/12+1/12


=10/12= 5/6

Leya [2.2K]3 years ago
5 0

Answer:

5/6.

Step-by-step explanation:

If Heba ate 1/12 of a box of cereal and the box is now 3/4 full, then before she ate the box is 3/4 plus the 1/12 (because, in the "before" situation she hasn't eaten yet). So, we need to add the "now" quantity and the quantity eaten:

\frac{3}{4}+\frac{1}{12} = \frac{10}{12} = \frac{5}{6}.

Then, before she ate the cereal, the box is 5/6 full.

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What is the inverse of A(r)=15+3r
mel-nik [20]

Answer:

A(r)=15-3r

Step-by-step explanation:

switch the sign of +3r to make it -3r

5 0
3 years ago
Help me please now I need to give it today​
Hoochie [10]

9/24=3/8=0.375

42/45=14/15=0.933

84/18=14/3=4.666

6 0
3 years ago
Solve the letter f question please
olga2289 [7]

Answer:

  3 79/100

Step-by-step explanation:

  3\dfrac{1}{5}+2\dfrac{1}{5}\div\dfrac{5}{11}-3\dfrac{2}{5}\times\left(-1\dfrac{1}{4}\right)\qquad\text{given}\\\\=\dfrac{16}{5}+\left(\dfrac{11}{5}\cdot\dfrac{11}{5}\right)-\left(\dfrac{17}{5}\cdot\dfrac{5}{4}\right)\\\\=\dfrac{16}{5}+\dfrac{121}{25}-\dfrac{17}{4}=\dfrac{320+484-425}{100}=\dfrac{379}{100}\\\\=\boxed{3\dfrac{79}{100}}

8 0
2 years ago
ryan has a mix of action and sports games for a total of 39 video games his action collection is three more than half his sports
iVinArrow [24]

Answer:

He have <u>15</u> action games and <u>24</u> sports games.

Step-by-step explanation:

Given:

Ryan has a mix of action and sports games for a total of 39 video games his action collection is three more than half his sports collection.

Now, to find the number of action games and sports games.

Let the sports games be x.

As, given his action collection is three more than half his sports collection.

Thus, the action games = 3+\frac{x}{2} .

Total number of video games = 39.

So, we set an equation to get the number of action games and sports games:

x+(3+\frac{x}{2})=39

x+3+\frac{x}{2} =39

<em>Subtracting both sides by 3 we get:</em>

x+\frac{x}{2} =36

\frac{2x+x}{2}=36

\frac{3x}{2} =36

<em>Multiplying both sides by 2 we get:</em>

3x=72

<em>Dividing both sides by 3 we get:</em>

x=24.

<u>The sports games he have = 24.</u>

Now, to get the action games we substitute the value of x:

3+\frac{x}{2}

= 3+\frac{24}{2}

= 3+12

= 15.

<u>The action games he have = 15.</u>

Therefore, he have 15 action games and 24 sports games.

6 0
3 years ago
A principal believes 50% of her music students reported their practice hours accurately. Based on that assumption, she ran 200 s
Alex17521 [72]

Answer:

C. unlikely

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

A probability is said to be extremely likely if it is 95% or higher, and extremely unlikely if it is 5% or lower. A probabilty higher than 50% and lower than 95% is said to be likely, and higher than 5% and lower than 50% is said to be unlikely.

In this problem, we have that:

\mu = 0.48, \sigma = 0.18

How likely is it that a single survey would return a mean of 30%?

We have to find the pvalue of Z when X = 0.30.

Z = \frac{X - \mu}{\sigma}

Z = \frac{0.30 - 0.48}{0.18}

Z = -1

Z = -1 has a pvalue of 0.1587.

So the correct answer is:

C. unlikely

4 0
3 years ago
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