The answer to your question is 33/50 cause that is what I found on goggle
f(x) - g(x)
=> (3x² + x - 3) - (x² - 5x + 1)
=> 3x² + x - 3 - x² + 5x - 1
=> 3x² - x² + x + 5x - 3 - 1
=> 2x² + 6x - 4
1) Put all the numbers in numerical order :
15, 23, 24, 25, 25, 25, 27
The median is the middle of the numbers : 25
Mode is the value that occurs more often : 25
2) Put all the numbers in numerical order :
2, 3, 3, 3, 3, 4, 4, 5
The middle of the numbers is 3 and 3
so, 3 + 3 = 6
6 : 2 = 3
Median = 3
Mode = 3
3) Put all the numbers in numerical order :
5, 7, 8, 9, 9, 10, 10, 10, 12
Median = 9
Mode = 10
4) Put all the numbers in numerical order :
0, 1, 1, 2, 2, 3, 3, 3, 4, 4
Median
2 + 3 = 5 : 2 = 2,5
Mode = 3
5) Put all the numbers in numerical order :
12, 13, 15, 18, 25
Median = 15
Mode = 0 (None)
6) Put all the numbers in numerical order :
1, 1, 2, 2, 3, 3, 3, 4, 4, 4, 5
Median = 3
Mode = 3 and 4
7) Put all the numbers in numerical order :
6, 8, 9, 10, 10, 12
Median
9 + 10 = 19 : 2 = 8
Mode = 10
8) Put all the numbers in numerical order :
28, 30, 30, 30, 30, 31, 31, 31, 31, 31, 31, 31
Median
31 + 31 = 62 : 2 = 31
Mode = 31
The empirical probability of a 4 or 5 is
(count of outcome = 4 or 5)/(count of all outcomes) = (44 +40)/240 = 7/20
The problem statement asks you to assume the outcomes will remain in this proportion going forward. That is, the number of outcomes (n) of 4 or 5 in the next 60 rolls of the number cube is expected to satisfy
7/20 = n/60
Multiplying that by 60 gives
n = 60*(7/20) = 21
Selection D is appropriate.