1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Rus_ich [418]
3 years ago
9

What is the area of this figure?

Mathematics
1 answer:
Lapatulllka [165]3 years ago
3 0

9514 1404 393

Answer:

  54 square units

Step-by-step explanation:

One way to find the area is to divide the figure into 3 parts using a horizontal line at y=3.

The trapezoid below the line has bases 9 and 7, and height 6, so an area of ...

  A = (1/2)(b1 +b2)h

  A = (1/2)(9 +7)(6) = 48 . . . . square units

The left triangle above the line has a base of 3 and a height of 2, so an area of ...

  A = (1/2)bh

  A = (1/2)(3)(2) = 3 . . . . square units

The right triangle above the line has a base of 6 and a height of 1, so an area of ...

  A = (1/2)(6)(1) = 3 . . . . square units

Then the total area is ...

  figure area = trapezoid area + left triangle area + right triangle area

  figure area = (48 + 3 + 3) square units = 54 square units

You might be interested in
A line is defined by the equation y = 2/3 x - 6 The line passes through a point whose y-coordinate is 0. What is the x-coordinat
Iteru [2.4K]

Answer:

x = 9

Step-by-step explanation:

Use the equation of the line, and let y = 0. Then solve for x.

y = 2/3 x - 6

Let y = 0:

0 = 2/3 x - 6

Add 6 to both sides.

6 = 2/3 x

Multiply both sides by 3/2.

3/2 * 6 = x

x = 9

8 0
3 years ago
On a canoe trip, Rita paddled upstream (against the current) at an average speed of 2 mi/h relative to the riverbank. On the ret
Nikolay [14]

Answer:

B on edu2020

Step-by-step explanation:

4 0
3 years ago
The store bought a pair of shoes for $50, and sold it for $80.What percentage was the mark up
Charra [1.4K]
30% percent is what they marked up
6 0
3 years ago
Name an inscribed angle
Vladimir79 [104]

Answer:

BHF

Step-by-step explanation:

Definition of inscribed

6 0
3 years ago
Help Please? GEOMETRY Use the word bank to help you with possible answers (there are extra options that are not to be used)
ipn [44]
Short Answers:

Answer for part A: Definition of perpendicular
Answer for part B: Right Angle Congruence Theorem
Answer for part C: Reflexive Property of Congruence
Answer for part D: Definition of Midpoint
Answer for part E: \triangle SXR \cong \triangle TXR
Answer for part F: CPCTC

-------------------------------------------------------------

Explanations:

Part A:

We are given that \overline{RX} \perp \overline{ST} which means, in english, "line segment RX is perpendicular to line segment ST"

By the very definition of perpendicular, this means that the two line segments form a right angle. This is visually shown as the red square angle marker for angle RXT. Angle RXS is also a right angle as well.

---------------------
Part B:

The Right Angle Congruence Theorem (aka Right Angle Theorem) is the idea that if we have two right angles, then we know that they are both 90 degrees so they must be congruent to one another. 

---------------------
Part C:

Any line segment is congruent to itself. This is because any line segment will have the same length as itself. It seems silly to even mention something so trivial but it helps establish what we need for the proof. 

---------------------
Part D:

We are given "X is the midpoint of segment ST" so by definition, X is in the very exact middle of ST. Midpoints cut segments exactly in half. SX is one half while TX is the other half. The two halves are congruent which is why SX = TX

---------------------
Part E:

Writing \triangle SXR \cong \triangle TXR means "triangle SXR is congruent to triangle TXR". These two triangles are the smaller triangles that form when you draw in segment RX

Side Note: SAS stands for "side angle side". The angle must be between the two sides. The pairing RX and RX forms one of the 'S' letters (see part C), while the pairing SX and TX forms the other 'S' (see part D). The angles between the sides are RXS and RXT (see part B). 

---------------------
Part F:

CPCTC stands for "Corresponding Parts of Congruent Triangles are Congruent"

It means that if we have two congruent triangles, then the corresponding parts are congruent. Back in part E, we proved the triangles congruent. For this part, we look at the pieces RS and RT (which correspond to one another; they are the hypotenuse of each triangle). They are proven congruent by CPCTC

If CPCTC is an odd concept to think about, then try thinking about something like this: you have two houses which are completely identical in every way. We can say that those two houses are congruent. If the houses are identical, then surely every piece that makes up the house is identical to its corresponding piece to the other house. For example, the front door to each house is both the same size, shape, color, made of the same material, designed in the same pattern, etc. So the two doors are congruent as well.
8 0
3 years ago
Other questions:
  • Angela's car payment is due January 31. This bill is always paid automatically from her checking account. It is January 30 and A
    5·2 answers
  • Mariya is solving the quadratic equation by completing the square.
    5·2 answers
  • During the first stages of an epidemic, the number of sick people increases exponentially with time. Suppose that at = 0 days th
    11·1 answer
  • In the figure below, ΔGHF≅ΔEHD. Which statement is true by CPCTC?
    14·2 answers
  • Doug says that this clock shows 8:43.is he correct? Explain why or why not
    12·2 answers
  • PLZ HELP!!<br><br> Find the value of the missing Angles:
    7·1 answer
  • −−+negative 6 x y minus 3 x plus y
    13·1 answer
  • HELP PLEASE<br> here’s the question
    10·2 answers
  • 23.96448 to the nearest tenth
    12·2 answers
  • Express 6 time the difference of 20 and 6 divide by 7 and simplify​
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!