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Kipish [7]
3 years ago
14

Graph the points (-3,4) and (1,1). If you drew a line through the points, name three other points that would be on the line. How

did you find them?
Mathematics
1 answer:
Andrej [43]3 years ago
3 0
The easiest way to solve this problem is to find the equation of the line joining these two points, then get the values of the points on this line.

We have first point (x1,y1) = (-3,4) and second point (x2,y2) = (1,1).
The equation of the line is y = mx + c
The slope (m) = (y2-y1) / (x2-x1) = (1-4) / (1--3) = -0.75

Then we will use one of these points to get the value of c as follows:
y = mx + c
1 = -0.75 (1) + c ..............> c = 1.75

The equation of this straight line is:
y = -0.75 x + 1.75

Now to get points on this line, we will assume values for either x or y and calculate the other as follows:
1- For x = 0:
y = -0.75 (0) + 1.75 = 1.75
point is (0,1.75)
2- For y = 0:
0 = -0.75 x + 1.75 ..............> x = 2.334
point is (2.334,0)
3- For x = 2:
y = -0.75(2) + 1.75 = 0.25
point is (2,0.25)
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dimaraw [331]

Answer:

5a  

2

+4ab+5b  

2

Step-by-step explanation:

step  1. (((0-(4•(a2)))+3ab)+(12•(b2)))+(((9•(a2))+ab)-7b2)

 step 2. (((0-(4•(a2)))+3ab)+(12•(b2)))+((32a2+ab)-7b2)

step 3.(((0-(4•(a2)))+3ab)+(22•3b2))+(9a2+ab-7b2)

step 4. (((0-(4•(a2)))+3ab)+(22•3b2))+(9a2+ab-7b2)

step 5. 5.1    Factoring    5a2 + 4ab + 5b2

6 0
3 years ago
Determine the sum of the first seven terms 256+128+64+32+...​
vova2212 [387]

Answer:

I cannot see the rest of the terms. I only see 4.

Step-by-step explanation:

3 0
3 years ago
Given the function () = $
elena-s [515]

The inverse of the function f(x) = 1/3x^2 - 3x + 5 is  f-1(x) = 9/2 + √[3(x + 7/4)], the sum of the arithmetic series is 1078 and the common ratio of the sequence is 2

<h3>The inverse of the function?</h3>

The function is given as:

f(x) = 1/3x^2 - 3x + 5

Next, we rewrite the function as in vertex form

Using a graphing calculator, the vertex form of the function f(x) = 1/3x^2 - 3x + 5 is

f(x) = 1/3(x - 9/2)^2 - 7/4

Express f(x) as y

y = 1/3(x - 9/2)^2 - 7/4


Swap x and y

x = 1/3(y - 9/2)^2 - 7/4

Add 7/4 to both sides

1/3(y - 9/2)^2 = x + 7/4

Multiply through  by 3

(y - 9/2)^2 = 3(x + 7/4)

Take the square root of both sides

y - 9/2 = √[3(x + 7/4)]

Add 9/2 to both sides

y = 9/2 + √[3(x + 7/4)]

Rewrite as an inverse function

f-1(x) = 9/2 + √[3(x + 7/4)]

<h3>Sum of arithmetic series</h3>

Here, we have:

5 + 18 + 31 + 44 + ... 161

Calculate the number of terms using:

L = a + (n -1)d

So, we have:

161 = 5 + (n - 1) * 13

This gives

(n - 1) * 13 = 156

Divide by 13

n - 1 = 12

Add 1

n = 13

The sum is then calculated as:

Sn = n/2 * [a + L]

This gives

Sn =13/2 * (5 + 161)

Evaluate

Sn = 1078

Hence, the sum of the arithmetic series is 1078

<h3>The common ratio of the sequence</h3>

Here, we have:

T11  = 32 * T6

The nth term of a geometric sequence is

Tn = ar^(n-1)

This gives

ar^10 = 32 * ar^5

Divide by ar^5

r^5 = 32

Take the fifth root

r = 2

Hence, the common ratio of the sequence is 2


Read more about sequence at:

brainly.com/question/7882626

#SPJ1

6 0
2 years ago
The area of a gymnasium is (27x + 18) square units. Factor 27x + 18 to find possible dimensions of the gymnasium.
Veronika [31]

Answer:

Dimension of gymnasium= 9 units and (3x+2) units.

Step-by-step explanation:

We have been given the area of a gymnasium is 27x+18 square units. We are asked to find possible dimensions of gymnasium by factoring our given expression for area of gymnasium.

Let us factor our greatest common factor of our given expression. We can see that 9 is the GCF of our given expression.

(9\times 3x+9\times 2)

Upon factoring out 9 from our given expression we will get,

9(3x+2)

Therefore, the possible dimensions of the gymnasium will be 9 units and (3x+2) units as we will get the same area for gymnasium by multiplying these both dimensions.  

8 0
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kap26 [50]

Answer:

0/8

Step-by-step explanation:

Slope equals y 2 minus y 1 divided by x 2 minus x 1

-2-(-2)/6-(-2)

0/8

4 0
3 years ago
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