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3 years ago

What is nx25=5x60 and how did you get the answer?

Mathematics

1 answer:

asambeis [7]3 years ago

8 0

Hey there!

n * 25 = 5 * 60

25n = 5 * 60

25n = 300

DIVIDE 25 to BOTH SIDES

25n/25 = 300/25

CANCEL out: 25/25 because it gives you 1

KEEP: 300/25 because it helps solve for the n-value

NEW EQUATION: n = 300/25

SIMPLIFY IT!

n = 12

Therefore, your answer is: n = 12

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

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Find the measurement of E<br> •56<br> •132<br> •51<br> •63

Burka [1]

Answer:

∠ E = 56°

Step-by-step explanation:

the external angle of a triangle is equal to the sum of the 2 opposite interior angles.

∠ MGF is an exterior angle of the triangle , then

10x + 12 = 5x - 4 + 76

10x + 12 = 5x + 72 ( subtract 5x from both sides )

5x + 12 = 72 ( subtract 12 from both sides )

5x = 60 ( divide both sides by 5 )

x = 12

Then

∠ E = 5x - 4 = 5(12) - 4 = 60 - 4 = 56°

4 0

2 years ago

Read 2 more answers

You are a lifeguard and spot a drowning child 60 meters along the shore and 40 meters from the shore to the child. You run along

sukhopar [10]

Answer:

The lifeguard should run across the shore a distance of 48.074 m before jumpng into the water in order to minimize the time to reach the child.

Step-by-step explanation:

This is a problem of optimization.

We have to minimize the time it takes for the lifeguard to reach the child.

The time can be calculated by dividing the distance by the speed for each section.

The distance in the shore and in the water depends on when the lifeguard gets in the water. We use the variable x to model this, as seen in the picture attached.

Then, the distance in the shore is d_b=x and the distance swimming can be calculated using the Pithagorean theorem:

$d_s^2=(60-x)^2+40^2=60^2-120x+x^2+40^2=x^2-120x+5200\\\\d_s=\sqrt{x^2-120x+5200}$

Then, the time (speed divided by distance) is:

$t=d_b/v_b+d_s/v_s\\\\t=x/4+\sqrt{x^2-120x+5200}/1.1$

To optimize this function we have to derive and equal to zero:

$\dfrac{dt}{dx}=\dfrac{1}{4}+\dfrac{1}{1.1}(\dfrac{1}{2})\dfrac{2x-120}{\sqrt{x^2-120x+5200}} \\\\\\\dfrac{dt}{dx}=\dfrac{1}{4} +\dfrac{1}{1.1} \dfrac{x-60}{\sqrt{x^2-120x+5200}} =0\\\\\\ \dfrac{x-60}{\sqrt{x^2-120x+5200}} =\dfrac{1.1}{4}=\dfrac{2}{7}\\\\\\ x-60=\dfrac{2}{7}\sqrt{x^2-120x+5200}\\\\\\(x-60)^2=\dfrac{2^2}{7^2}(x^2-120x+5200)\\\\\\(x-60)^2=\dfrac{4}{49}[(x-60)^2+40^2]\\\\\\(1-4/49)(x-60)^2=4*40^2/49=6400/49\\\\(45/49)(x-60)^2=6400/49\\\\45(x-60)^2=6400\\\\$

$x$

As $d_b=x$ , the lifeguard should run across the shore a distance of 48.074 m before jumpng into the water in order to minimize the time to reach the child.

7 0

4 years ago

The following are questions from a self-quiz.According to some study, the height for Northern European adult males is normally d

lara [203]

Answer:

a) 0.064

b) 0.109

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 181 centimeter

Standard Deviation, σ = 7.3 centimeter

We are given that the distribution of height for Northern European adult males is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(person is between 160 and 170 centimeters)

$P(160 \leq x \leq 170) = P(\displaystyle\frac{160 - 181}{7.3} \leq z \leq \displaystyle\frac{170-181}{7.3}) = P(-2.8767 \leq z \leq -1.506)\\\\= P(z \leq -1.506) - P(z < -2.8767)\\= 0.066 -0.002 = 0.064 = 6.4\%$