Help me please! These are due today.

Mathematics

1 answer:

IrinaVladis [17]3 years ago

6 0

Answer:

${x}^{2} + 3x$

Step-by-step explanation:

Area of shaded region = Area of external rectangle - Area of internal rectangle

$= 4x(x + 2) - x(3x + 5) \\ = 4 {x}^{2} + 8x - 3 {x}^{2} - 5x \\ = 4 {x}^{2} - 3 {x}^{2} + 8x - 5x \\ = {x}^{2} + 3x \\$

Let the width of the rectangle be x inches.

Therefore, length of the rectangle = (x + 3) inches

Area of rectangle

$=(x + 3)\times x\\=x^2 + 3x\\$

Width of rectangle = 4 inches

Length of rectangle = 4 + 3 = 7 inches

Area of rectangle = 7*4 = 28 square inches.

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Consider from x = -5 to x = -4, they are 1 unit apart and the difference of their outputs is given by:

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The length of a rectangle is 3 times the width. If the perimeter is to be greater than 56 meter. What are the lossible values fo

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Answer:

w > 7

Step-by-step explanation:

L = 3w

2L + 2w > 56

sub for L

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