Answer:
x = 20
Step-by-step explanation:
Solve for x by simplifying both sides of the equation, then isolating the variable.
Answer:
Option d) 5 to the power of negative 5 over 6 is correct.
![\dfrac{\sqrt[3]{\bf 5} \times \sqrt{\bf 5}}{\sqrt[3]{\bf 5^{\bf 5}}}= 5^{\frac{\bf -5}{\bf 6}}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Csqrt%5B3%5D%7B%5Cbf%205%7D%20%5Ctimes%20%5Csqrt%7B%5Cbf%205%7D%7D%7B%5Csqrt%5B3%5D%7B%5Cbf%205%5E%7B%5Cbf%205%7D%7D%7D%3D%205%5E%7B%5Cfrac%7B%5Cbf%20-5%7D%7B%5Cbf%206%7D%7D)
Above equation can be written as 5 to the power of negative 5 over 6.
ie, 
Step-by-step explanation:
Given that cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.
It can be written as below
![\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Csqrt%5B3%5D%7B5%7D%20%5Ctimes%20%5Csqrt%7B5%7D%7D%7B%5Csqrt%5B3%5D%7B5%5E5%7D%7D)
![\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}} \times 5^{\frac{1}{2}}}{5^{\frac{5}{3}}}](https://tex.z-dn.net/?f=%20%5Cdfrac%7B%5Csqrt%5B3%5D%7B5%7D%20%5Ctimes%20%5Csqrt%7B5%7D%7D%7B%5Csqrt%5B3%5D%7B5%5E5%7D%7D%3D%20%5Cdfrac%7B5%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%20%5Ctimes%205%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%7D%7B5%5E%7B%5Cfrac%7B5%7D%7B3%7D%7D%7D)
![\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}+\frac{1}{2}}}{5^{\frac{5}{3}}}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Csqrt%5B3%5D%7B5%7D%20%5Ctimes%20%5Csqrt%7B5%7D%7D%7B%5Csqrt%5B3%5D%7B5%5E5%7D%7D%3D%20%5Cdfrac%7B5%5E%7B%5Cfrac%7B1%7D%7B3%7D%2B%5Cfrac%7B1%7D%7B2%7D%7D%7D%7B5%5E%7B%5Cfrac%7B5%7D%7B3%7D%7D%7D)
![\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{2+3}{6}}}{5^{\frac{5}{3}}}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Csqrt%5B3%5D%7B5%7D%20%5Ctimes%20%5Csqrt%7B5%7D%7D%7B%5Csqrt%5B3%5D%7B5%5E5%7D%7D%3D%20%5Cdfrac%7B5%5E%7B%5Cfrac%7B2%2B3%7D%7B6%7D%7D%7D%7B5%5E%7B%5Cfrac%7B5%7D%7B3%7D%7D%7D)
![\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5}{6}} \times 5^{\frac{-5}{3}}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Csqrt%5B3%5D%7B5%7D%20%5Ctimes%20%5Csqrt%7B5%7D%7D%7B%5Csqrt%5B3%5D%7B5%5E5%7D%7D%3D%205%5E%7B%5Cfrac%7B5%7D%7B6%7D%7D%20%5Ctimes%205%5E%7B%5Cfrac%7B-5%7D%7B3%7D%7D)
![\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5-10}{6}}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Csqrt%5B3%5D%7B5%7D%20%5Ctimes%20%5Csqrt%7B5%7D%7D%7B%5Csqrt%5B3%5D%7B5%5E5%7D%7D%3D%205%5E%7B%5Cfrac%7B5-10%7D%7B6%7D%7D)
![\dfrac{\sqrt[3]{5} \times \sqrt{5}}{5^5}= 5^{\frac{-5}{6}}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Csqrt%5B3%5D%7B5%7D%20%5Ctimes%20%5Csqrt%7B5%7D%7D%7B5%5E5%7D%3D%205%5E%7B%5Cfrac%7B-5%7D%7B6%7D%7D)
Above equation can be written as 5 to the power of negative 5 over 6.
Answer:
170 ft²
Step-by-step explanation:
Given:
Patio drawing of 4.25 in by 2.5 in
Scale of Patio to its drawing = 4ft to 1 in
Requires:
Area of actual Patio
SOLUTION:
Area of actual Patio = area of a rectangle = length × width
Given a scale drawing of 4ft to 1 in, therefore:
Length of actual Patio = 4.25 × 4 = 17 ft
Width of actual Patio = 2.5 × 4 = 10 ft
Therefore:
Area of actual Patio = 17 ft × 10 ft = 170 ft²
Answer:
15y / 8
Step-by-step explanation:
Multiplying by 2 to get the common denominator.
3y / 4 * 2 = 6y / 8
Combine like terms.
6y / 8 + 9y / 8
Final Answer:
15y / 8