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Grace [21]
3 years ago
15

Lynn has a watering can that holds 32 cups of water, and she fills it a quarter full. Then she waters her 23 plants so that each

plant gets the same amount of water. How many cups of water will each plant get?
Mathematics
1 answer:
Arlecino [84]3 years ago
6 0
.3478 is the answer, round however you like
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Find the value of x in the following equation: x⁄2 + 2x⁄5 = 18.
butalik [34]

Answer:

x = 20

Step-by-step explanation:

Solve for  x  by simplifying both sides of the equation, then isolating the variable.

8 0
3 years ago
Read 2 more answers
Evaluate cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.
Andre45 [30]

Answer:

Option d)  5 to the power of negative 5 over 6 is correct.

\dfrac{\sqrt[3]{\bf 5} \times \sqrt{\bf 5}}{\sqrt[3]{\bf 5^{\bf 5}}}= 5^{\frac{\bf -5}{\bf 6}}

Above equation can be written as 5 to the power of negative 5 over 6.

ie, 5^\frac{\bf -5}{\bf 6}

Step-by-step explanation:

Given that cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.

It can be written as below

\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}

\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}} \times 5^{\frac{1}{2}}}{5^{\frac{5}{3}}}

\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}+\frac{1}{2}}}{5^{\frac{5}{3}}}

\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{2+3}{6}}}{5^{\frac{5}{3}}}

\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5}{6}} \times 5^{\frac{-5}{3}}

\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5-10}{6}}

\dfrac{\sqrt[3]{5} \times \sqrt{5}}{5^5}= 5^{\frac{-5}{6}}

Above equation can be written as 5 to the power of negative 5 over 6.

7 0
3 years ago
A contractor is given a scale drawing of a rectangular patio. The scale from the patio to the drawing is 4ft to 1in. What is the
AnnyKZ [126]

Answer:

170 ft²

Step-by-step explanation:

Given:

Patio drawing of 4.25 in by 2.5 in

Scale of Patio to its drawing = 4ft to 1 in

Requires:

Area of actual Patio

SOLUTION:

Area of actual Patio = area of a rectangle = length × width

Given a scale drawing of 4ft to 1 in, therefore:

Length of actual Patio = 4.25 × 4 = 17 ft

Width of actual Patio = 2.5 × 4 = 10 ft

Therefore:

Area of actual Patio = 17 ft × 10 ft = 170 ft²

5 0
2 years ago
PLEASE SIMPLIFY THIS<br>​
AnnyKZ [126]

Answer:

15y / 8

Step-by-step explanation:

Multiplying by 2 to get the common denominator.

3y / 4 * 2 = 6y / 8

Combine like terms.

6y / 8 + 9y / 8

Final Answer:

15y / 8

3 0
3 years ago
What is the probability that the first spinner lands on a number even greater than 5 and the second spinner lands on purple?
Alexxandr [17]
3/32
Gfggdsdfghhhvvdffghj
4 0
3 years ago
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