Answer:
PART A
- Red: 7/29
- Blue: 8/29
- Yellow: 5/29
- Green: 9/29
PART B
- Red or blue: 7/29 + 8/29 = 15/29
- Yellow or green: 5/29 + 9/29 = 14/29
- Blue or yellow or green: 8/29 + 5/29 + 9/29 = 22/29
Explanation:
In this case where the question is asking or <u>OR</u> and the events are <u>mutually exclusive</u> (Mutually exclusive meaning you can't attain two or three different colors in one pick), the compound probability is the sum of the probability of each component event (Probability of Red <u>OR</u> Blue = P(Red) + P(Blue) = 7/29 + 8/29 = 15/29)
That's more than 275 million stars per day in the observable universe. Stars keep themselves fueled. They fuse elements together to make new elements.Once the star runs out of hydrogen, the helium atoms fuse together to make carbon.
I would have to go with social learning
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Answer:
Amount to spend = $18.50
Purchased banana =$1.50
Apple Juice =$1.55
Gasoline $2.35
$1.50 + $1.55 = $3.05
18.50 - 3.05 = 15.45
1 Gallon of Gasoline = 2.35
Therefore,
2.35 x 6 = 14.1
15.35 - 14.1 = 1.25
To avoid exceeding budget, he can only buy
6 gallons of gasoline
Using the normal approximation to the binomial, it is found that there is a 0.0107 = 1.07% probability that more than 30 are single.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean
and standard deviation
is given by:

- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
- The binomial distribution is the probability of x successes on n trials, with p probability of a success on each trial. It can be approximated to the normal distribution with
.
In this problem, the proportion and the sample size are, respectively, p = 0.22 and n = 200, hence:


The probability that more than 30 are single, using continuity correction, is P(X > 30.5), which is <u>1 subtracted by the p-value of Z when X = 30.5</u>, hence:


Z = -2.3
Z = -2.3 has a p-value of 0.0107.
0.0107 = 1.07% probability that more than 30 are single.
More can be learned about the normal distribution at brainly.com/question/24663213