You can figure out the answer by doing this:
8% = 2300/x
and do the same for the second one
(and solve)
Answer:
x: work a woman can do in 1 day
y: work a girl can do in 1 day
Then
2x + 7y =1/4
4x + 4y =1/3
4x + 14y =2/4 (1)
4x + 4y =1/3 (2)
=> Let (1) - (2), 10y =2/4-1/3 <=>10y = 1/6 <=> y = 1/(6x10) = 1/60 (work)
=> From (2),4x = 1/3 - 4x1/60 => 4x = 16/60 => x = 4/60 (work)
=> 1 day, a woman and a girl can do: 1/60+4/60 = 5/60 =1/12 (work)
Then, the day required for a woman and a girl to complete work: 12 days
1 and 1/2 hours each night
1+1+1+1+1= 5
1/2+1/2+1/2+1/2+1/2= 2.5
5+2.5= 7.5
7.5 hours or & and a half
hope this helps
~L
Answer:
Loss section
Step-by-step explanation:
Given
-- cost
-- revenue
Required
Determine where n = 150 is
To do this, we substitute 150 for n in the given functions
The above shows that the revenue is greater than cost for n = 150.
This implies that, n = 15o is the loss section.
