Question

A reta que passa pelos pontos (2,-1) e (6,4) intersecta o eixo das abcissas no ponto (x,0) onde x é igual a:

Answer 1

Answer:

$x=2.8$

Step-by-step explanation:

we are given that

line passes through (2,-1) and (6,4)

Firstly, we will find equation of line

First point is (2,-1)

x1=2, y1=-1

second point is (6,4)

x2=6 , y2=4

now, we can find slope

$m=\frac{y_2-y_1}{x_2-x_1}$

now, we can plug values

$m=\frac{4+1}{6-2}$

$m=\frac{5}{4}$

now, we can use point slope form of line

$y-y_1=m(x-x_1)$

now, we can plug values

$y+1=\frac{5}{4}(x-2)$

since, we have to solve for x from (x,0)

so, we can set y=0

and then we can solve for x

$0+1=\frac{5}{4}(x-2)$

$5\left(x-2\right)=4$

$x-2=\frac{4}{5}$

$x=\frac{14}{5}$

$x=2.8$