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Naily [24]
3 years ago
13

Find the value of given expression

ula1" title=" \sqrt{564 \times 564} " alt=" \sqrt{564 \times 564} " align="absmiddle" class="latex-formula">


​
Mathematics
2 answers:
uranmaximum [27]3 years ago
8 0

Answer:

√(564×564)=√564²=±564

stellarik [79]3 years ago
6 0

Answer:

±564.

Step-by-step explanation:

\sqrt{564 \times 564}

\sqrt{ {564}^{2} }

±564.

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Solve (x - 2 < 5) U (x + 7 > 6).
dolphi86 [110]

Answer:

A) {x | -1 < x < 7}

Step-by-step explanation:

Given in the question two inequalities,

Inequality 1

(x - 2 < 5)

 x < 5 + 2

 x < 7

x is smaller than 7

Inequality 2

(x + 7 > 6)

 x > 6 - 7

 x > -1

x is greater then -1

When (x - 2 < 5) U (x + 7 > 6).

              (x < 7)   U  (x > -1)    

                    -1 <  x  < 7

When combined, x is greater than -1 but smaller than 7

8 0
4 years ago
A ball is dropped from the top of a building.
Marat540 [252]

Answer:

D because if the ball already dropped all the potential energy from the height has been used

8 0
3 years ago
Read 2 more answers
PLEASE HELP ASAP!!!
Alborosie

Answer:

(2,6)

Step-by-step explanation:

Since its reflecting on the y axis, the rule for that is (-x,y) for x the sign changes, and y stays the same. The coordinates for Q are (-2,6) and when you use the rule itll come out to (2,6)

4 0
3 years ago
Einsteinium-
Natalija [7]

Answer:

                 S(t)=450(2/3)^t

Explanation:

The question is "Einstenium-253 is an element that loses about 2/3 of its mass every month. A sample of einstenium-253 has 450 grams. Write a function that gives the sample's mass in grams, S(t) from today".

Since <em>einstenium-253 loses about 2/3 of its mass every month</em>, you can model the amount of sample by an exponential decay function, which is a geometric progression with a growing factor less than 1.

The general form of an exponential decay function is:

y=A_0r^t

Where:

  • A₀ is the initial value
  • r is the growing or decaying factor
  • t is the time
  • y is the value of the function at time t.

In this case, you have:

  • A₀ = 450
  • r = 2/3
  • t = t
  • y = S(t)

Now you can replace the values in the model and will obtain:

                  S(t)=450(2/3)^t

4 0
3 years ago
2. What is the effective annual rate of an investment that pays 6% for 5 years, compounded semiannually?
Ede4ka [16]

Answer:

effective annual rate is 6.16 %

Step-by-step explanation:

given data

rate = 6 % = 0.06

time 5 year = 10 semi annually

to find out

effective annual rate

solution

we know formula for annual effective rate of interest is

rate of  interest = (1+ r/n)^{n} -1

put here all value

rate of interest = (1+ 0.06/10)^{10} -1

rate of  interest = (1+ 0.06/10)^{10} -1

rate of interest = 0.061646

so effective annual rate is 6.16 %

8 0
4 years ago
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