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german
4 years ago
7

Identify the translation rule on a coordinate plane that verifies that triangle A(-5,1), B(-2,7), C(0,1) and triangle A'(-3,2),

B'(0,8), C'(2,2) are congruent.
A) (x, y) → (x - 1, y + 2)
B) (x, y) → (x + 2 , y + 1)
C) (x, y) → (x - 2, y + 1)
D) the triangles are not congruent
Mathematics
2 answers:
maxonik [38]4 years ago
8 0

Answer:

The answer is B.

Explanation:

(x, y) → (x + 2, y + 1) is correct.

Every <u>point</u> of a figure is moved the same <u>distance</u> in the same direction to form the new figure. <u>Translation</u> does not change the size or shape, angles or <u>line</u> lengths of a figure.

Please rate Brainliest (:

alexira [117]4 years ago
7 0
The answer is B
first, look at all the x coordinates:
-5+2=-3, -2+2=0, 0+2=2
then, look at all the y coordinates:
1+1=2, 7+1=8, 1+1=2

All the three points are translated in the same way, that is, right 2 units, up 1 unit. the two triangles are congruent.
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The coordinate plane below represents a city. Points A through F are schools in the city. graph of coordinate plane. Point A is
Ray Of Light [21]
Part A;
There are many system of inequalities that can be created such that only contain points A and E in the overlapping shaded regions.

Any system of inequalities which is satisfied by (2, -3) and (3, 1) but is not satisfied by (-3, -4), (-4, 2), (2, 4) and (-2, 3) can serve.

An example of such system of equation is
y ≤ x
y ≥ -2x
The system of equation above represent all the points in the first quadrant of the coordinate system.
The area above the line y = -2x and to the right of the line y = x is shaded.



Part B:
It can be verified that points A and E are solutions to the system of inequalities above by substituting the coordinates of points A and E into the system of equations and see whether they are true.

Substituting A(2, -3) into the system we have:
-3 ≤ 2
-3 ≥ -2(2) ⇒ -3 ≥ -4
as can be seen the two inequalities above are true, hence point A is a solution to the set of inequalities.

Also, substituting E(3, 1) into the system we have:
1 ≤ 3
1 ≥ -2(3) ⇒ 1 ≥ -6
as can be seen the two inequalities above are true, hence point E is a solution to the set of inequalities.



Part C:
Given that William can only attend a school in her designated zone and that William's zone is defined by y < −x - 1.

To identify the schools that William is allowed to attend, we substitute the coordinates of the points A to F into the inequality defining William's zone.

For point A(2, -3): -3 < -(2) - 1 ⇒ -3 < -2 - 1 ⇒ -3 < -3 which is false

For point B(-3, -4): -4 < -(-3) - 1 ⇒ -4 < 3 - 1 ⇒ -4 < 2 which is true

For point C(-4, 2): 2 < -(-4) - 1 ⇒ 2 < 4 - 1 ⇒ 2 < 3 which is true

For point D(2, 4): 4 < -(2) - 1 ⇒ 4 < -2 - 1 ⇒ 4 < -3 which is false

For point E(3, 1): 1 < -(3) - 1 ⇒ 1 < -3 - 1 ⇒ 1 < -4 which is false

For point F(-2, 3): 3 < -(-2) - 1 ⇒ 3 < 2 - 1 ⇒ 3 < 1 which is false

Therefore, the schools that Natalie is allowed to attend are the schools at point B and C.
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7/8, 8/9, 0.98

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What is the distributive property of 364×26
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4 years ago
Find the distance between A(2, -9) and B(-5, 7) on a coordinate plane d=?
Kazeer [188]

Answer:

d=17.4642

Step-by-step explanation:

Distance Formula: d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Simply plug in your 2 coordinates into the distance formula to find distance <em>d</em>:

d=\sqrt{(-5-2)^2+(7-(-9))^2}

d=\sqrt{(-7)^2+(7+9)^2}

d=\sqrt{49+(16)^2}

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3.21 kilometers is the answer to this question.
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