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GenaCL600 [577]
3 years ago
8

5 root 12 + 4 root 12 - 3 root 18 + 75​

Mathematics
1 answer:
oee [108]3 years ago
7 0

5√12+4√12-3√18+75

5+4√12-3√18+75

9√12-3√9×√2+75

9√12+3√2+75

9√4×3+3√2+75

9×2√3+3√2+75

18√3+3√2+75

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Christian randomly selects students from his grade to rate a math test as easy, moderate, or difficult. Of the students he surve
IRINA_888 [86]

Answer:

84

Step-by-step explanation:

Total students he surveyed: 27

Amount that found it something OTHER than easy: 14 (11 moderate + 3 difficult)

This means that \frac{14}{27} found it something other than easy

Multiply that by 162 to find the proportion for the larger population:

162 * (14/27), and we get 84.

4 0
2 years ago
Based on the scatterplot below what is most likely the value for “pounds of apples” when “Numbers of Apples” is 60
kari74 [83]

Answer:

36

Step-by-step explanation:

8 0
4 years ago
The arm and blade of a windshield wiper have a total length of 30 inches. The blade is 24 inches long and the wiper sweeps out a
Ipatiy [6.2K]

Answer:

942.5 in²  

Step-by-step explanation:

The formula for the area (A) of a sector of a circle is

A = ½r²θ

where θ is the angle in radians.

1. Convert the angle to radians

θ = 125°  

\theta = 125^{\circ} \times \dfrac{\pi \text{ rad }}{180^{\circ}} =\frac{25}{36} \pi\text{ rad}

2. Area swept out by wiper arm

A = ½r²θ = ½ × (30 in)² × θ = ½ × 900 in²× θ = 450 θ in²

3. Area missed by wiper

A = ½r²θ = ½ × (6 in)² × θ = ½ × 36 in²× θ = 18 θ in ²

4. Area covered by wiper

A = 450 θ in² - 18 θ in² = 432 θ in²

5. Insert the value of θ

A = 432 × 25/36 π in² = 300π in² ≈ 942.5 in²

The area swept out by the wiper blade is 942.5 in².

6 0
4 years ago
Add (8b - 7) + (6b + 8) simplify the answers. Pls show steps
katovenus [111]
I’m not rlly sure if i did it right & i’m sorry if i didn’t. i used the FOIL method
f= first to first
o=outer to outer
i=inner to inner
l= last to last
so it’d be
8b + 6b = 14b (f)
8b+ 8=16b(o)
-7+6b=-1b(i)
-7+8(l)
and then you add like terms so
[14b+16b-1b]+1
= 29b+1
7 0
3 years ago
If given the following AP what is the common difference 10, 15, 20
ANTONII [103]

Answer:

The common difference of the given AP is d=5.

Step-by-step explanation:

Given the sequence

10,\:15,\:20

An Arithmetic sequence has a constant difference 'd' and is defined by

a_n=a_1+\left(n-1\right)d

Computing the common difference of all the adjacent terms

10,\:15,\:20

15-10=5,\:\quad \:20-15=5

As the difference between all the adjacent terms is the same and equal to

d=5

Therefore, the common difference of the given AP is d=5.

6 0
3 years ago
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