5 root 12 + 4 root 12 - 3 root 18 + 75

Michaels buys three over a pound of cheese he puts the same amount of cheese and three sandwiches how many cheese how much chees

Tasya [4]

Question is not proper,Proper question is given below;

Nicholas buys 3/8 pound of cheese he put the same amount of cheese and three sandwiches how much cheese does Nicholas put on each sandwich

Answer:

Nichole can put $\frac{1}{8} \ pounds$ of cheese on each of his sandwich.

Step-by-step explanation:

Total Amount of cheese he has = $\frac{3}{8} \ pound$

Number of cheese sandwiches = 3

We need to find Amount of cheese does Nicole put on each of his sandwich.

Solution:

Amount of cheese on each sandwich can be calculated by dividing Total Amount of cheese he has with Number of cheese sandwiches.

framing in equation form we get;

Amount of cheese on each sandwich = $\frac{\frac{3}{8}}{3}} = \frac{1}{8} \ pounds$

Hence Nichole can put $\frac{1}{8} \ pounds$ of cheese on each of his sandwich.

7 0

3 years ago

Which of the following statements is true if m∠E = m∠Y and m∠F = m∠X?

mars1129 [50]

Answer:

segment FE over segment XY equals segment EG over segment YZ equals segment GF over segment ZX

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

If m∠E = m∠Y and m∠F = m∠X

then

Triangles EFG and YXZ are similar by AA Similarity Theorem

Remember that

If two figures are similar, then the ratio of its corresponding sides is proportional and its corresponding angles are congruent

In this problem

The corresponding sides are

FE and XY

EG and YZ

GF and ZX

so therefore

segment FE over segment XY equals segment EG over segment YZ equals segment GF over segment ZX Firstly , let us learn about trigonometry in mathematics.

Suppose the ΔABC is a right triangle and ∠A is 90°.

sin ∠A = opposite / hypotenuse

cos ∠A = adjacent / hypotenuse

tan ∠A = opposite / adjacent

Let us now tackle the problem!

A similar triangle has the same angle, in other words the triangle has the same shape but different sizes.

From the figure in the attachment , we can conclude that:

m∠E = m∠Y

m∠F= m∠X

m∠G = m∠Z

∴ ΔEFG ~ ΔYXZ ( ΔEFG is similar to ΔYXZ )

Because of the similarity , then:

FE : XY = EG : YZ = GF : ZX

Conclusion:

ΔFG is similar to ΔYXZ.

Segment FE over segment XY equals segment EG over segment YZ equals segment GF over segment ZX , i.e:

Keywords: Sine , Cosine , Tangent , Opposite , Adjacent , Hypotenuse , Triangle , Fraction , Lowest , Function , Angle

3 0

2 years ago

Read 2 more answers

HELP PLEASE 10 POINTS!!!!!! A country's population in 1993 was 171 million. In 1999 it was 176 million. Estimate the population

Lilit [14]

Let 1993 = time 0 = 0.

Let 1999 = time 6 = 6

Let 2012 = time 19 = 19

So, a = 171 (million). First solve for k.

176 = 171 e^k6

176/171 = e^(k*6)

ln (176/171) = 6k

k = 1/6 ln (176/171)

So, in 2012 we have: P(19) = 171 e^(19k), where k = 1/6 ln (176/171)

Hope this helped!

3 0

3 years ago

Can i have some help pls

user100 [1]

Answer:

the first recipe

Step-by-step explanation:

We can answer by finding the ratio of nuts to cereal. The one that has the higher ratio of nuts to cereal is the nuttier one.

Recipe 1: 2 1/2 cups of nut per 5 cups of cereal.

nuts to cereal ratio = 2 1/2 : 5 = 1 : 2

Recipe 2: 1 cups of nuts per 3 cups of cereal.

nuts to cereal ratio = 1 : 3

1 : 2 is a higher ratio than 1 : 3

Answer: the first recipe

3 0

2 years ago

In the following problem, check that it is appropriate to use the normal approximation to the binomial. Then use the normal dist

Tcecarenko [31]

Answer:

a. 0.7291

b. 0.9968

c. 0.7259

Step-by-step explanation:

a. np and n(1-p) can be calculated as:

$np=23\times 0.48\\\\=11.04\\\\n(1-p)=23(1-0.52)\\\\=11.96$

#Both np and np(1-p) are greater than 5, hence, normal approximation is most appropriate:

$\mu_x=11.04\\\\\sigma^2=np(1-p)=0.48\times 0.52\times 23=5.7408$

#Define Y:

Y~(11.04,5.7408)

$P(X\leq 12)\approx P(Y\leq 12.5)\\\\P(Z\leq \frac{(12.5-11.04)}{\sqrt{5.7408}})=\\\\=1-0.2709\\\\=0.7291$

Hence, the probability of 12 or fewer is 0.8291

b. The probability that 5 or more fish were caught.

#Using normal approximation:

$P(X \geq 5) \approx P(Y \geq 4.5) = P(Z \geq\frac{ (4.5-11.04)}{\sqrt{(5.7408)}})\\\\=1-0.0032\\\\=0.9968$

Hence, the probability of catching 5+ is 0.9968

c. The probability of between 5 and 12 is calculated as;

-From b above $P(X\geq 5)=0.9968$ and a , $P(X\leq 12)$ =0.7291

$P(5\leq X\leq 120\approx P(4.5\leq Y\leq 12.5)\\\\=0.7291-(1-0.9968)\\\\=0.7259$

Hence, the probability of between 5 and 12 is 0.7259

4 0

3 years ago

5 root 12 + 4 root 12 - 3 root 18 + 75​

5 root 12 + 4 root 12 - 3 root 18 + 75