The answer is C 102 degrees. It is so because a triangles 3 angles add up to 180 degrees. If you know 2 of your angles, you would add them together and subtract that by 180 to find your last angle.
Answer:
5 + 2
Step-by-step explanation:
5 + - 
+ +
5 + 2 - +
5 + 2
Answer:
44.47 cm² (nearest hundredth)
Step-by-step explanation:
Area of ΔABC = 1/2 x base x height
⇒ 21 = 1/2 x 7 x BC
⇒ BC = 6 cm
Pythagoras' Theorem: a² + b² = c²
(where a and b are the legs, and c is the hypotenuse, of a right triangle)
⇒ AB² + BC² = AC²
⇒ 7² + 6² = AC²
⇒ AC² = 85
⇒ AC = √85 cm
Cosine rule to find length AD:
c² = a² + b² - 2 ab cosC
⇒ DC² = AD² + AC² - 2(AD)(AC)cos(DAC)
⇒ 9.2² = AD² + (√85)² - 2(AD)(√85)cos 73°
⇒ AD² - 5.39106...AD + 0.36 = 0
⇒ AD = 5.323442445, 0.06762541414
⇒ AD = 5.323442445
Area of a triangle ADC: (1/2)absinC
(where a and b are adjacent sides and C is the angle between them)
⇒ area = (1/2) × AC × AD × sin(DAC)
⇒ area = (1/2) × √85 × 5.323442445 × sin(73°)
⇒ area =23.4675821... cm²
Area of quadrilateral = area of ΔABC + area of ΔADC
= 21 + 23.4675821...
= 44.47 cm² (nearest hundredth)
Answer:
$2247
Step-by-step explanation:
2100+(2100*7/100)= 2100+147=2247
Answer:
Step-by-step explanation:
Given
sunny day speed= s mph
Rainy day speed=s+1 mph
Derek average speed =2.8 miles/hr
s<2.8<s+1
so on sunny day speed must be 2 mph
and on rainy day speed must be 3 mph
Let x be the distance traveled in sunny and y be the distance traveled in rainy weather
Let 
Fraction of distance traveled on sunny weather
