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dlinn [17]
3 years ago
5

How long will it take for a $4000 investment to grow to $6000 at an annual rate of 15%, compounded monthly? Assume that no withd

rawals are made. Do not round any intermediate computations, and round your answer to the nearest hundredth.
Business
1 answer:
Inessa05 [86]3 years ago
6 0

Answer:

It will take 2.72 years and 32.64 months.

Explanation:

Future value is the sum of principal amount and compounded interest amount invested on a specific rate for a specific period of time.

Use following formula to calculate the time period.

FV = PV x ( 1+ r )^n

FV = Future value = $6,000

PV = Present Value =  $4,000

r = rate of interest = 15% yearly = 15% / 12 = 1.25%

n = time period = ?

$6,000 = $4,000 x ( 1 + 1.25% )^n

$6,000 = $4,000 x ( 1.0125 )^n

$6,000 / $4,000 = ( 1.0125 )^n

1.5 = ( 1.0125 )^n

Log 1.5 = n log 1.0125

n = Log 1.5 / log 1.0125

n = 32.64 months

n = 2.72 years

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5 0
3 years ago
Cindy invests $10000 in an account that pays an annual rate of 3.96%, compounding semi-annually. approximately how much does she
stiks02 [169]

Annual Compound Formula is:

A = P( 1 + r/n) ^nt

Where:

A is the future value of the investment

P is the principal investment

r is the annual interest rate

<span>n is the number of  interest compounded per year</span>

t is the number of years the money is invested


So for the given problem:

P = $10,000

r = 0.0396

n = 2 since it is semi-annual

t = 2 years

 

Solution:

A = P( 1 + r/n) ^nt

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As of December 31, 2015, Juneau Company had total cash of $155,000, notes payable of $85,600, and common stock of $52,400. Durin
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Answer:

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Explanation:

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net income

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dividends: 3,000

ending RE: 17,000 + 16,000 - 3,000 = 30,000

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