Answer:
B) Because you are adding positively charged protons, which pull in the outer electrons.
Explanation:
Since the increase in protons have a greater effect then the increase in electrons the protons pull the electrons in closer resulting the radius of an atom to decrease from left to right across a period.
You spelled calendar incorrectly, the correct spelling is the one I previously wrote...Calendar
Answer:
Na⁺ and HCO⁻₃
Explanation:
When baking soda is dissolve in water it fully ionized into positive and negative ions.
NaHCO₃ + H₂O → Na⁺ + HCO⁻₃
The Na⁺ than react with OH⁻ of water and produced NaOH while HCO⁻₃ react with H⁺ and produce H₂CO₃. This carbonic acid than break to produced carbon dioxide and water.
H₂CO₃ → H₂O + CO₂
Properties of baking soda:
It is odorless compound.
It is solid at room temperature.
It is used in medicine to cure the acidity of stomach.
It is used to make baking powder.
Explanation:
The pH of a substance can be found by using the formula
![pH = - log[ H^{ + } ]](https://tex.z-dn.net/?f=pH%20%3D%20%20-%20%20log%5B%20H%5E%7B%20%2B%20%7D%20%20%5D)
where [ H+ ] is the hydrogen ion concentration in the substance
From the question
[ H+ ] = 2.1 × 10-¹² M
To find the pH substitute the value into the above formula
We have
We have the answer as
<h2>pH = 11.7 </h2>
The solution is basic since it lies in the basic region that is from 8 to 14
Hope this helps you
Answer:
5. The valence electrons of both fluorine and carbon are found at about the same distance from their respective nuclei but the greater positive charge of the fluorine nucleus attracts its valence electrons more strongly.
Explanation:
Both fluorine and carbon are located in the second period of the periodic table, it means that they have 2 shells, so the valence electrons are found at about the same distance from their respective nuclei.
But fluorine has a higher atomic number, 9, than the carbon, 6. The atomic number represents how many protons there are in the nucleus, then there are more protons (positive charge) at the fluorine nucleus, and because of that, the attraction force between the nucleus and the valence electron is stronger in fluorine.
If the force is stronger, it will be necessary more energy to break the bond, so it will be harder to remove an electron from fluorine than from carbon.
