If two protons are removed from an oxygen nucleus, the result is

Biology

1 answer:

riadik2000 [5.3K]4 years ago

6 0

Ummmmm..... probably a very difficult question

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. As arteries extend outward they decrease in thickness until they turn into microscopic vessels known as_ ((frog dissection))

sveticcg [70]

ANSWER: The correct answer is CAPILLARIES

EXPLANATION: Arteries are the muscular wall tube that carries oxygenated blood from the heart to other part of the body. The arteries extend outward from the heart, and form capillaries.

The capillaries are hairlike thinnest blood vessels, that helps to join the arteries and ventricles together. The blood in the arteries extends to the capillaries of the organs where the blood is supplied, and then moves out to from the organ via the ventricles.

The capillary starts from the part of the arteries that are very thin.

7 0

3 years ago

The first steps in glycolysis involve

Nat2105 [25]

Answer:

E I think

Explanation:

Turning glucose into pyruvates (Glucose got split)

4 0

2 years ago

Which statement most correctly describes the role of a connecting proteins A. It connects the carbohydrate tag with the correct

Llana [10]

D. it serves as a link between membrane proteins on adjacent membranes.

4 0

3 years ago

Plsssssss help me.......

sdas [7]

A. 50% are pink and 50% are white, if you do the table it shouldn’t be as hard

B. Yes because RW includes the WW from White but it could take a couple offspring to get Red (from my understanding from last year)

8 0

3 years ago

Two humans mate who are heterozygous for earlobe shape where attached earlobes (A) are dominant to free earlobes (a), and earwax

MariettaO [177]

Answer:

3/16

Explanation:

This question involves two different genes coding for earlobe shape and earwax quality. The alleles for attached earlobes (A) and wet earwax (E) are dominant over the alleles for free earlobes (a) and dry earwax (e).

According to this question, two humans mate who are heterozygous for both genes i.e. AaEe × AeEe. Each parent will produce the following gametes: AE, Ae, aE, ae.

Using these gametes in a punnet square (see attached image), the following proportion of offsprings will be produced:

* Attached earlobe, wet earwax (A_E_) = 9/16

* Attached earlobe, dry earwax (A_ee) = 3/16

* Free earlobe, wet earwax (aaE_) = 3/16

* Free earlobe, dry earwax (aaee) = 1/16

Hence, the probability of these parents having their first child with dry earwax (ee) and attached earlobes (A_) i.e. genotype A_ee is 3/16.

7 0

3 years ago