Answer:
If 
whenever 
f is <em>increasing</em> on I.
If 
whenever f is <em>decreasing</em> on I.
Step-by-step explanation:
These are definitions for real-valued functions f:I→R. To help you remember the definitions, you can interpret them in the following way:
When you choose any two numbers on I and compare their image under f, the following can happen.
- . Because x2 is bigger than x1, you can think of f also becoming bigger, that is, f is increasing. The bigger the number x2, the bigger f becomes.
- . The bigger the number x2, the smaller f becomes so f is "going down", that is, f is decreasing.
Note that this must hold for ALL choices of x1, x2. There exist many functions that are neither increasing nor decreasing, but usually some definition applies for continuous functions on a small enough interval I.
Answer:
<u><em>9 months</em></u>
Step-by-step explanation:
Principal= P= $1200
Rate=R= 15%
Interest= I= $135
Time= T= ?
I=P*R*T/100
135= 1200*15*T/100
135*100=18000*T
13500/18000=T
T= 0.75 years
T= 0.75*12= 9 months
-7 + -5
When you add negative, it would be the same as subtracting
Turns into: -7-5
-(7+5) = -12
The solutions is -12
21. 1/7 3/8 1/2
23. 3 5/8 3 3/8 3 1/2
25. 1/6 3/4 2/3
