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Elan Coil [88]
4 years ago
9

Please please help me

Mathematics
1 answer:
larisa [96]4 years ago
8 0
The answer is multiplied by 5
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-(x+3) = 2x-6 what is x
Makovka662 [10]

Answer:

x=1

Step-by-step explanation:

So, first you make sure to multiply the parenthesis by the negative so then it would be,

-x-3=2x-6

Then you add the -3 from the right to the other side

so, -x=2x-3

Then you want all the X variables to one side so you subtract the 2x to both sides.

so, -3x=-3

divide both by -3

x=1

7 0
3 years ago
Write the sentence as an equation,<br><br> Four times the difference of -10 and 3 amounts to -52.
mars1129 [50]

Answer:

4*(-10-(-3))=-52

Step-by-step explanation:

just step by step

4 0
3 years ago
What equation is solved by the graphed systems of equations? 7x + 3 = x + 3 7x − 3 = x − 3 7x + 3 = x − 3 7x − 3 = x + 3
Romashka [77]
It's the first option, I'm pretty sure.
Hope this helps!!
3 0
4 years ago
PLEASE HELP ME!!!!!!!!!
Simora [160]
The answer is X < 12
4 0
3 years ago
Read 2 more answers
Quadratic Equation
Natasha_Volkova [10]

Step-by-step explanation:

The sum of ages of two friends is 13 years.

The product of their ages is 42.

<em>Let the age of 1st friend and 2nd friend is x, y respectively.</em>

<em>1 st condition= The sum of ages of two friends is 13 y</em><em>r</em><em>s. </em>

i.e x+y = 13........ (I)

<em>2nd condition= The product of their ages is 42.</em>

i.e X*y = 42........(ii)

From equation (I)

X+y = 13

or, X = 13-y........ (iii)

<em>Putting the equation (iii) in equation (ii).</em>

X*y= 42

(13-y) * y = 42

13y - y^2 = 42

{y}^{2}  - 13y + 42 = 0

{y}^{2}   - (7 + 6)y + 42= 0

{y}^{2}  - 7y - 6y + 42 = 0

y(y - 7) - 6(y - 7) = 0

(y - 6) (y - 7) = 0

Either; y-6 = 0

y = 6

Or;

y-7=0

y = 7

<em>Keeping the value of y as "7" in equation (ii)</em>

x*y = 42

7x = 42

X = 42/7

Therefore, the value of X is 6.

Therefore, either 1st friend is 6 years and 2nd is 7 years.

<em><u>H</u></em><em><u>o</u></em><em><u>p</u></em><em><u>e</u></em><em><u> </u></em><em><u>it </u></em><em><u>helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

7 0
3 years ago
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