Answer:
The outer circle is 16 feet larger than the inner circle (68 - 52).
Step-by-step explanation:
Given that the inner circle circumference is 52 feet, and the distance between the inner and the outer circle is 8 feet, to determine by how many ft is the larger outer circle, the following calculation must be performed:
The radius of a circle is equal to half its diameter. Therefore, the radius of the inner circle is 26 feet. Thus, if the distance between the two circles is 8 feet, the radius of the outer circle is 34 feet (26 + 8). Therefore, the diameter of this circle is 68 feet (34 x 2).
This implies that the outer circle is 16 feet larger than the inner circle (68 - 52).
So lets just assume that y = 1 since 2x is most likely an even number.
Then we can say that 2x = 8
8 divided by 2 is 4
so a point on this line could be (4,1)
Hope this helped
Answer:
3+2i
Step-by-step explanation:
(3x² -7x⁴) from (5x² - 3x⁸)
= 5x² - 3x⁸ - (3x² -7x<span>⁴ )
= </span> 5x² - 3x⁸ - 3x² + 7x<span>⁴
= </span>- 3x⁸ + 7x⁴ + 5x² <span>- </span><span>3x²
</span>
= - 3x<span>⁸ </span>+ 7x⁴ + 2x<span>²</span>
What is the missing number in the list of perfect squares 1,4,9,16,25,36,49,_,81,100,121,144
Yuri [45]
Answer:
64
Step-by-step explanation:
49= 7*7
81=9*9
8*8=64
