So lets try to prove it,
So let's consider the function f(x) = x^2.
Since f(x) is a polynomial, then it is continuous on the interval (- infinity, + infinity).
Using the Intermediate Value Theorem,
it would be enough to show that at some point a f(x) is less than 2 and at some point b f(x) is greater than 2. For example, let a = 0 and b = 3.
Therefore, f(0) = 0, which is less than 2, and f(3) = 9, which is greater than 2. Applying IVT to f(x) = x^2 on the interval [0,3}.
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Answer:
at least 6
Step-by-step explanation:
3(.5x+3)>12
1.5x+9>12
1.5>9
x>6
If 6.45 is supposed to be miles
6.45 miles = 10380.269 metres
10380.269+15+500=10,895.269
but that is only if the 6.45 is in miles
The 3 inside angles of a triangle need to equal 180 degrees.
The angle below the 100 degrees would be 180-100 = 80 degrees.
Now you have 80 and 70, which equals 150 degrees.
Angle X = 180 -150 = 30 degrees
