4 years ago

Cos(inv) {(a+bcosx)/(b+acosx)} Differentiate...

1 answer:

6 0

Differentiation of Cos(inv) {(a+bcosx)/(b+acosx)} = -(((a + b Cos[x])/(Sqrt[1 - x^2] (b + ArcCos[x])^2) - (b Sin[x])/(b + ArcCos[x]))/Sqrt[1 - (a + b Cos[x])^2/(b + ArcCos[x])^2])

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