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bonufazy [111]
4 years ago
14

Cos(inv) {(a+bcosx)/(b+acosx)} Differentiate...

Mathematics
1 answer:
Kay [80]4 years ago
6 0
<span>Differentiation of </span><span>Cos(inv) {(a+bcosx)/(b+acosx)} =</span><span> -(((a + b Cos[x])/(Sqrt[1 - x^2] (b + ArcCos[x])^2) - (b Sin[x])/(b + ArcCos[x]))/Sqrt[1 - (a + b Cos[x])^2/(b + ArcCos[x])^2])</span>

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