Answer:
The answer to your question is x = 6 and y = 9
Step-by-step explanation:
Data
AB = x DF = 18
BC = 5 FE = 15
AC = 3 DE = y
Process
1.- Find y
Use proportions to find it
DE/FE = AC/BC
Substitution
y/15 = 3/5
Solve for y
y = 15(3/5)
y = 45/5
y = 9
2.- Find x
AB/DF = BC/FE
Substitution
x/18 = 5/15
Solve for x
x = 18(5/15)
x = 90/15
x = 6
Answer:
-15
Step-by-step explanation:
Class F=36.6666666667%
class E=33.3333333333%
class H=41.6666666667%
class G=<span>32%</span>
<h3>
Answer: -16n-41</h3>
Work Shown:
2(-n-3) -7(5+2n)
2(-n)+2(-3) - 7(5)-7(2n) ... distribute
-2n - 6 - 35 - 14n
(-2n-14n) + (-6-35)
-16n - 41
Answer:
Let two consecutive multiples of 3 be x and (x+3)
A/q,
x * (x+3) = 648
➡ x² + 3x = 648
➡ x² + 3x -648 = 0
➡ x² + 27x - 24x -648 = 0
➡ x ( x + 27 ) -24 ( x +27)
➡ ( x - 24) ( x + 27)
➡ x = 24 and x = -27
so, we take x = 24.
Required multiples of 3
➡ x = 24
➡ x +3 = 24+3 = 27.
