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2 years ago

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He graph represents part of Brooke's trip to work. During what time period is her speed increasing?

1 answer:

iogann1982 [59]2 years ago

5 0

Her speed is increasing between A) 0 - 10 minutes.

You can see this because the graph line is inclining. Everywhere else it is either staying the same (her speed is neither increasing or decreasing) or declining ( slowing down).

20 - 25 she is decreasing.
10 - 20 she is going the same speed.

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Can u plz help me look at the photo<br><br> PLZ NO LINKS

djyliett [7]

Answer:

0.07

Step-by-step explanation:

The hundredths place is the place between the tenths and thousandths place. For example, the digit in the tenths place in 0.073 is 7.

To round to the nearest hundredth, we look to the digit right of the hundredth digit, 7. We notice that the digit in the thousandths place is 3. When rounding, if a number is 4 or less, we change that digit to a 0, along with the digits beyond it. If a number is 5 or more, we bump up the digit to the next number. Since 3 is less than 4, we change 0.073 to 0.07.

Have a lovely rest of your day/night, and good luck with your assignments! ♡

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2 years ago

Factor the following expression: 16z+20

Evgen [1.6K]

Answer:

4z + 5

Step-by-step explanation:

16 and 20 are both dividable by 4, so you divide them both by four and then you have your answer

3 0

2 years ago

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If b/a=2/5, what is the value of 2 (a/b)

Nina [5.8K]

$\dfrac{b}{a}=\dfrac{2}{5}\to\dfrac{a}{b}=\dfrac{5}{2}\ \ \ |\cdot2\\\\2\left(\dfrac{a}{b}\right)=2\cdot\dfrac{5}{2}\\\\2\left(\dfrac{a}{b}\right)=5$

Answer: 2(a/b) = 5

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2 years ago

I am giving away points if you answer this Question<br><br> What is 2+2

Setler79 [48]

Answer:

4 heh

Step-by-step explanation:

mark me brainliest plz

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3 years ago

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Let X denote the distance (m) that an animal moves from its birth site to the first territorial vacancy it encounters. Suppose t

andrezito [222]

Answer and Step-by-step explanation: For an exponential distribution, the probability distribution function is:

f(x) = λ. $e^{-\lambda.x}$

and the cumulative distribution function, which describes the probability distribution of a random variable X, is:

F(x) = 1 - $e^{-\lambda.x}$

(a) <u>Probability</u> of distance at most <u>100m</u>, with λ = 0.0143:

F(100) = 1 - $e^{-0.0143.100}$

F(100) = 0.76

<u>Probability</u> of distance at most <u>200</u>:

F(200) = 1 - $e^{-0.0143.200}$

F(200) = 0.94

<u>Probability</u> of distance between <u>100 and 200</u>:

F(100≤X≤200) = F(200) - F(100)

F(100≤X≤200) = 0.94 - 0.76

F(100≤X≤200) = 0.18

(b) The mean, E(X), of a probability distribution is calculated by:

E(X) = $\frac{1}{\lambda}$

E(X) = $\frac{1}{0.0143}$

E(X) = 69.93

The standard deviation is the square root of variance,V(X), which is calculated by:

σ = $\sqrt{\frac{1}{\lambda^{2}} }$

σ = $\sqrt{\frac{1}{0.0143^{2}} }$

σ = 69.93

<u>Distance exceeds the mean distance by more than 2σ</u>:

P(X > 69.93+2.69.93) = P(X > 209.79)

P(X > 209.79) = 1 - P(X≤209.79)

P(X > 209.79) = 1 - F(209.79)

P(X > 209.79) = 1 - (1 - $e^{-0.0143*209.79}$ )

P(X > 209.79) = 0.0503

(c) Median is a point that divides the value in half. For a probability distribution:

P(X≤m) = 0.5

$\int\limits^m_0 f({x}) \, dx$ = 0.5

$\int\limits^m_0 {\lambda.e^{-\lambda.x}} \, dx$ = 0.5

$\lambda.\frac{e^{-\lambda.x}}{-\lambda}$ = $-e^{-\lambda.x} + e^{0}$

$1 - e^{-\lambda.m}$ = 0.5

$-e^{-\lambda.m}$ = - 0.5

ln( $e^{-0.0143.m}$ ) = ln(0.5)

-0.0143.m = - 0.0693

m = 48.46

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3 years ago