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Bingel [31]
4 years ago
15

There is no answer choices. I really need help with this! prime factorize (expand) the expression 12a^3bd^5

Mathematics
1 answer:
Molodets [167]4 years ago
3 0
\bf 12a^3bd^5\qquad 
\begin{cases}
12=2\cdot 2\cdot 3\\
a^3=a\cdot a\cdot a\\
d^5=d\cdot d\cdot d\cdot d\cdot d
\end{cases}\implies (2)(2)(3)aaabddddd

is all I can see, I mean, you can't kill a dead horse, you can hit it, it won't make it deader, just flatter.
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Identify the polygon with vertices A(5,0), B(2,4), C(−2,1), and D(1,−3), and then find the perimeter and area of the polygon. HE
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Answer:

Part 1) The polygon is a square

Part 2) The perimeter is equal to 20\ units

Part 3) The area is equal to 25\ units^{2}

Step-by-step explanation:

we have

A(5,0), B(2,4), C(-2,1),D(1,-3)

Plot the points

see the attached figure

we know that

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

Find the distance AB

A(5,0),B(2,4)

substitute in the formula

d=\sqrt{(4-0)^{2}+(2-5)^{2}}

d=\sqrt{(4)^{2}+(-3)^{2}}

d=\sqrt{25}

AB=5\ units

Find the distance BC

B(2,4), C(-2,1)

substitute in the formula

d=\sqrt{(1-4)^{2}+(-2-2)^{2}}

d=\sqrt{(-3)^{2}+(-4)^{2}}

d=\sqrt{25}

BC=5\ units

Find the distance CD

C(-2,1),D(1,-3)

substitute in the formula

d=\sqrt{(-3-1)^{2}+(1+2)^{2}}

d=\sqrt{(-4)^{2}+(3)^{2}}

d=\sqrt{25}

CD=5\ units

Find the distance AD

A(5,0),D(1,-3)

substitute in the formula

d=\sqrt{(-3-0)^{2}+(1-5)^{2}}

d=\sqrt{(-3)^{2}+(-4)^{2}}

d=\sqrt{25}        

AD=5\ units

we have that

AB=BC=CD=AD

Find the distance BD (diagonal)

B(2,4),D(1,-3)

substitute in the formula

d=\sqrt{(-3-4)^{2}+(1-2)^{2}}

d=\sqrt{(-7)^{2}+(-1)^{2}}

BD=\sqrt{50}\ units        

<em>Verify if the polygon is a square</em>

If the triangle BDA is a right triangle, then the polygon is a square

Applying the Pythagoras theorem

BD^{2}=AD^{2}+AB^{2}

substitute

(\sqrt{50})^{2}=5^{2}+5^{2}

50=50 -----> is true

so

The triangle BDA is a right triangle

therefore

The polygon is a square

<em>Find the Area of the polygon</em>

The area of a square is equal to

A=b^{2}

we have

b=5\ units

A=5^{2}=25\ units^{2}

<em>Find the perimeter of the polygon</em>

The perimeter of a square is equal to

P=4b

we have

b=5\ units

P=4(5)=20\ units

6 0
3 years ago
A bakery has the following pricing for large orders of cupcakes. The first 100 cupcakes of any order
Taya2010 [7]

A piecewise function is a function that behaves differently in different intervals of its domain.

The answers are:

a)

f(x) = x*$2.00    if 0 ≤ x ≤ 100

f(x) = x*$1.75     if  100 < x ≤ 250

f(x) = x*$1.25     if    x > 250.

b)  $306.25

The given information is:

The first 100 cupcakes cost $2.00 each.

If the order is between 100 and 250 cupcakes, the cost is $1.75 each.

If the order is more than 250 cupcakes, the cost is $1.25 each.

a) Now we want to write the piecewise function, this will be:

f(x) = x*$2.00    if 0 ≤ x ≤ 100

f(x) = x*$1.75     if  100 < x ≤ 250

f(x) = x*$1.25     if    x > 250.

Above you can see the piecewise function, when you want to evaluate it, the first thing you need to do is to find at which interval the input belongs.

b) If you order 175 cupcakes you have x = 175.

This belongs to the second interval ( 100 < x ≤ 250) then we will use the second part of the function:

f(175) = 175*$1.75 = $306.25

If you want to learn more, you can read:

brainly.com/question/12561612

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3 years ago
Factor completely 36x 2 + 60x + 25
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I believe that the answer is 90x+27
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RUDIKE [14]

Answer:

Step-by-step explanation:

It's D.

A theorem is true by some sort of mathematical logic.

It is not a definition. Not C

It is not in the end true because of inductive reasoning (a theorem may lend itself to inductive reasoning, but it must be proved.) Not A

It certainly not assumed to be true without proof. Not B

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3 years ago
Explain the process for finding the product of two integers
Marysya12 [62]
The process of finding the product of two integers is multiplying them. A product is the answer to a multiplication problem. 

E.g.: 

Integers: 5 and 2

5*2 or 5 x 2
=10

Product: 10
8 0
3 years ago
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