Question

In rectangle abcd measure of angle d =(3x+15) measure b =(6x-42) find measure of angle a

Answer 1

5) So for parallelogram ABCD, ∠B ≅ ∠D, and ∠A ≅ ∠C. Further, ∠B and ∠A are supplementary (i.e., their sum is 180°), and ∠D and ∠C are also supplementary.
So, we have that m∠B = m∠D. Therefore, 
$6x-42=3x+15\\3x=57\\x=19$

Now, let's substitute for x back into the expression for either ∠B or ∠D to find it's angle measure.
m∠B = $6(19)-42=72$
Now, remember that ∠B or ∠D are supplements of ∠A. 
So, m∠B + m∠A = 180°.
That means m∠A = 180° – 72° = 108°.
That seems reasonable, because A appears to be an obtuse angle.