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Advocard [28]
3 years ago
15

What is the difference between log(x/y) and log(x)/log(y)?

Mathematics
1 answer:
Yuliya22 [10]3 years ago
6 0
They are different equations lol. If you plug in the same x and y for both you wont get the same answer. Do you have answer choices? 
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If there are 1,200 calories in 8 oz of hot fudge, how many calories are in 1,500 men, how many women are there?
Allisa [31]
1200/8 = 150 thus, 150 per calorie. 150 x 3 = 450 :)
7 0
3 years ago
Solve for v<br><br> 3v+9-8v= -31<br> Simplify your answer as much as possible.
balandron [24]
Let's solve your equation step-by-step.
<span><span><span><span>3v</span>+9</span>−<span>8v</span></span>=<span>−31
</span></span>Step 1: Simplify both sides of the equation.
<span><span><span>−<span>5v</span></span>+9</span>=<span>−31
</span></span>Step 2: Subtract 9 from both sides.
<span><span><span><span>−<span>5v</span></span>+9</span>−9</span>=<span><span>−31</span>−9</span></span><span><span>−<span>5v</span></span>=<span>−40
</span></span>Step 3: Divide both sides by -5.
<span><span><span>−<span>5v</span></span><span>−5</span></span>=<span><span>−40</span><span>−5
</span></span></span><span>v=<span>8</span></span>
6 0
3 years ago
Which logarithmic equation is equivalent to the exponential equation below?
aleksandr82 [10.1K]

Option B: \ln 6=5 x is the correct answer.

Explanation:

The exponential equation is e^{5 x}=6

If f(x)=g(x), then \ln (f(x))=\ln (g(x))

Thus, the equation becomes

\ln \left(e^{5 x}\right)=\ln (6)

Applying log rule, \log _{a}\left(x^{b}\right)=b \cdot \log _{a}(x) and thus the equation becomes

5 x \ln (e)=\ln (6)

Since, we know that, \ln (e)=1, using this we get,

5 x=\ln (6)

Hence, the logarithmic equation which is equivalent to the exponential equation e^{5 x}=6 is \ln 6=5 x

Thus, Option B is the correct answer.

7 0
3 years ago
HELP ME PLEASE thank you so much to who helps me :)
igor_vitrenko [27]

Answer:

π(12.1)²

Step-by-step explanation:

12.1 is the radius

Formula for base = πr²

= π(12.1)²

3 0
2 years ago
How would you compare 3.6 and the root of 12?
Luden [163]

\sqrt{12}

can be simplify as

\sqrt{4}  \times  \sqrt{3}

= 2 \sqrt{3}

= 3.46

now comparing 3.6 to 3.46

we can say that

3.6 > 3.46 (√12)

8 0
4 years ago
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