T h e a n s w e r i s 2 3
The answer for this question is very tricky but is to work out its B.
Answer:
5.D1.3 select from among a variety of graphs, including stacked-bar graphs, the type of graph best suited to represent various sets of data; display
Step-by-step explanation:
Step-by-step explanation:
the third option is the right answer
Answer:
0.05 + 0.1y = 0.12 + 0.06y
Step-by-step explanation:
Here, we want to find y which is the heat in which the amount of mercury in each of the water bodies is same.
Now for the first water body:
Initial is 0.05 ppb and after y years, we have a rise of 0.1 * y = 0.1y ppb
So the amount of mercury in ppb after y years would be; 0.05 + 0.1y
For the second water body;
Initial is 0.12 and a rise of 0.06 ppb per year for y years. The rise would be 0.06 * y = 0.06y
So total amount of mercury here is 0.12 + 0.06y
So to find y which is the year the amount of mercury in each water body is same, we simple equate both and that would be;
0.05 + 0.1y = 0.12 + 0.06y
