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svetoff [14.1K]

3 years ago

11

Rachel is driving from New York to Dayton Florida a distance of 1034 miles. How Much Time Is Saved By Doing The Trip At An Avera

ge Speed Of 60mph as compared with 55 mph? Round to the nearest half hour

1 answer:

balandron [24]3 years ago

4 0

Answer:

If she is driving 60 mph she will save 1 hour of her time rather then going 55 mph.

Step-by-step explanation:

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Express 38% as a fraction in simplest form.

Gnoma [55]

Answer:

19/50

Step-by-step explanation:

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3 years ago

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Two similar polygons have areas of 16 square inches and 64 square inches. The ratio of a pair of corresponding sides is 1/4.

Luden [163]

Your answer is A. True.

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3 years ago

How do you graph y=|x|+2

xenn [34]

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3 years ago

Show that if S1 and S2 are subsets of a vector space V such that S1 c S2 then span(S1) c span(S2). In particular, if S1 c S2 the

klemol [59]

Answer:

See proof below

Step-by-step explanation:

Assume that V is a vector space over the field F (take F=R,C if you prefer).

Let $x\in span(S_1)$ . Then, we can write x as a linear combination of elements of s1, that is, there exist $v_1,v_2,\cdots,v_k \in S_1$ and $a_1,a_2,\cdots,a_k\in F$ such that $x=a_1v_1+a_2v_2+\cdots+a_kv_k$ . Now, $S_1\subseteq S_2$ then for all $y\in S_1$ we have that $y\in S_2$ . In particular, taking $y=v_j$ with $j=1,2,\cdots,k$ we have that $v_j\in S_2$ . Then, x is a linear combination of vectors in S2, therefore $x\in span(S_2)$ . We conclude that $span(S_1)\subseteq span(S_2)$ .

If, additionally $S_2\subseteq S_1$ then reversing the roles of S1 and S2 in the previous proof, $span(S_2)\subseteq span(S_1)$ . Then $span(S_1)\subseteq span(S_2)\subseteq span(S_1)$ , therefore $span(S_1)=span(S_2)$ .

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3 years ago

hury!!!! Which system is equivalent to StartLayout Enlarged left-brace 1st row y = negative 2 x squared 2nd row y = x minus 2 En

jeka57 [31]

Answer:

3rd Option

Step-by-step explanation:

Which equation is the inverse of y = 7x2 – 10?

y = StartFraction plus-or-minus StartRoot x + 10 EndRoot Over 7 EndFraction

y = plus-or-minus StartRoot StartFraction x + 10 Over 7 EndFraction EndRoot

x = plus-or-minus StartRoot StartFraction x Over 7 EndFraction + 10 EndRoot

y = StartFraction plus-or-minus StartRoot x EndRoot Over 7 EndFraction plus-or-minus StartFraction StartRoot 10 EndRoot Over 7 EndFraction

8 0

3 years ago

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