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We are given 2 sides 18.7, 16.1 and a NON-included angle.
We have to calculate the altitude of the triangle.
altitude = 18.7 * sine (35)
altitude = 18.7 * 0.57358
altitude = <span> <span> <span> 10.725946 </span> </span> </span>
In this case, side c is greater than the altitude and is less than side a so 2 two triangles will be formed.
Source:
http://www.1728.org/trigssa.htm
We have to calculate the altitude of the triangle.
altitude = 18.7 * sine (35)
altitude = 18.7 * 0.57358
altitude = <span> <span> <span> 10.725946 </span> </span> </span>
In this case, side c is greater than the altitude and is less than side a so 2 two triangles will be formed.
Source:
http://www.1728.org/trigssa.htm
Answer:
1. 144 2. 16 3. 1 4. 3x-6
Step-by-step explanation:
So think of this as a function in a function. So you work from the inside to the outside. So for problem 1, we start with f(4)) [you read it "f of 4"] so what is the solution when x = 4, since f(x) means the function of x so f(4) means 'the function of 4' inside f(x).
Since f(x) = 3x then f(4) = 3(4) [notice how you substitute the 4 everywhere you see a letter x]
so f(4) = 12, now you work the next part h(f(4)) since f(4)=12 then h(12)
So take the h(x) function which is h(x) = then h(12) =
so h(12) = 144
Answer:
(-5, 0) ∪ (5, ∞)
Step-by-step explanation:
I find a graph convenient for this purpose. (See below)
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When you want to find where a function is increasing or decreasing, you want to look at the sign of the derivative. Here, the derivative is ...
f'(x) = 4x^3 -100x = 4x(x^2 -25) = 4x(x +5)(x -5)
This has zeros at x=-5, x=0, and x=5. The sign of the derivative will be positive when 0 or 2 factors have negative signs. The signs change at the zeros. So, the intervals of f' having a positive sign are (-5, 0) and (5, ∞).
