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AnnZ [28]
3 years ago
9

Express the area of a rectangle of x+6 and x+2

Mathematics
1 answer:
noname [10]3 years ago
3 0

Answer:

x²+8x+12, do the distributive property

Step-by-step explanation:

x+6 times x+2 is equal to x(x+2) and 6(x+2) , that will leave you with x²+2x and 6x+12. Add these together to get x²+8x+12

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A sprinter ran 100 meter dash in 10.92 seconds. What was the sprinters speed in miles per hour
tresset_1 [31]
The formula for working out speed :

speed = distance ÷ time.

substitute the numbers : 100m ÷ 10.92s.

give your answer in meters per second ( m/s )

the answer I got while working this out was:
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8 0
3 years ago
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the number in each block is the sum of the numbers in the two blocks beneath it. Some of the numbers are hidden. What is the val
m_a_m_a [10]

Answer:

y - x = 69

Step-by-step explanation:

From the figure attached,

Number in each block is the sum of the numbers in the block beneath it.

Therefore, A + 21 = 32 ⇒ A = 11

A + 5 = B ⇒ B = 16

C = 5 + x

D = 32 + B ⇒ D = 32 + 16 = 48

E = B + C ⇒ E = 16 + (5 + x)

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y = D + E ⇒ y = 48 + (21 + x)

                   y = 48 + 21 + x

                   y = 69 + x

              y - x = 69

Therefore, y - x = 69 will be the answer.

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3 years ago
Jesse is helping his grandmother plant a garden in the shape of the trapezoid shown below. What is the area, in square feet, of
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Answer:

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Solve the following using Substitution method<br> 2x – 5y = -13<br><br> 3x + 4y = 15
Digiron [165]

\huge \boxed{\mathfrak{Question} \downarrow}

Solve the following using Substitution method

2x – 5y = -13

3x + 4y = 15

\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}

\left. \begin{array}  { l  }  { 2 x - 5 y = - 13 } \\ { 3 x + 4 y = 15 } \end{array} \right.

  • To solve a pair of equations using substitution, first solve one of the equations for one of the variables. Then substitute the result for that variable in the other equation.

2x-5y=-13, \: 3x+4y=15

  • Choose one of the equations and solve it for x by isolating x on the left-hand side of the equal sign. I'm choosing the 1st equation for now.

2x-5y=-13

  • Add 5y to both sides of the equation.

2x=5y-13

  • Divide both sides by 2.

x=\frac{1}{2}\left(5y-13\right)  \\

  • Multiply \frac{1}{2}\\ times 5y - 13.

x=\frac{5}{2}y-\frac{13}{2}  \\

  • Substitute \frac{5y-13}{2}\\ for x in the other equation, 3x + 4y = 15.

3\left(\frac{5}{2}y-\frac{13}{2}\right)+4y=15  \\

  • Multiply 3 times \frac{5y-13}{2}\\.

\frac{15}{2}y-\frac{39}{2}+4y=15  \\

  • Add \frac{15y}{2} \\ to 4y.

\frac{23}{2}y-\frac{39}{2}=15  \\

  • Add \frac{39}{2}\\ to both sides of the equation.

\frac{23}{2}y=\frac{69}{2}  \\

  • Divide both sides of the equation by 23/2, which is the same as multiplying both sides by the reciprocal of the fraction.

\large \underline{ \underline{ \sf \: y=3 }}

  • Substitute 3 for y in x=\frac{5}{2}y-\frac{13}{2}\\. Because the resulting equation contains only one variable, you can solve for x directly.

x=\frac{5}{2}\times 3-\frac{13}{2}  \\

  • Multiply 5/2 times 3.

x=\frac{15-13}{2}  \\

  • Add -\frac{13}{2}\\ to \frac{15}{2}\\ by finding a common denominator and adding the numerators. Then reduce the fraction to its lowest terms if possible.

\large\underline{ \underline{ \sf \: x=1 }}

  • The system is now solved. The value of x & y will be 1 & 3 respectively.

\huge\boxed{  \boxed{\bf \: x=1, \: y=3 }}

8 0
2 years ago
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