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Ivahew [28]
4 years ago
10

Write an equation of the vertical line through the points (9,-8)

Mathematics
1 answer:
Anna007 [38]4 years ago
5 0

Answer:

x = 9

Step-by-step explanation:

The equation of a vertical line parallel to the y- axis is

x = c

where c is the value of the x- coordinates the line passes through.

The line passes through (9, - 8) with x- coordinate 9, thus

x = 9 ← equation of vertical line

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Find the amount in an account where $500 is invested at 2.5% compounded continuously for period of 10 years
Alex17521 [72]

Hi

500 *1.025^10 ≈ 640.04

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3 years ago
3x+10+x solve for x thank you :)
weeeeeb [17]

Answer:

4x + 10

Step-by-step explanation:

8 0
3 years ago
A rope is 250 centimeters long. You need the rope to be 1 1/2 meters long. How many centimeters should you cut off?
Drupady [299]
If you would like to know how many centimeters should you cut off, you can calculate this using the following steps:

1 1/2 meters = 3/2 meters = 1.5 meters = 150 centimeters

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6 0
3 years ago
Solve this equation and explain the steps<br> 9-2x= 7x
Hunter-Best [27]

Answer:

x = 1

Step-by-step explanation:

Step 1: Write equation

9 - 2x = 7x

Step 2: Solve for <em>x</em>

<u>Add 2x on both sides:</u> 9 = 9x

<u>Divide both sides by 9:</u> x = 1

Step 3: Check

<em>Plug in x to verify it's a solution.</em>

9 - 2(1) = 7(1)

9 - 2 = 7

7 = 7

3 0
3 years ago
Write the general polynomial p(x) if its only zeros are 1 4 and -3 with multiplicites 3 2 and 1 respectively what is the degree
kompoz [17]

Answer:

The 6th degree polynomial is p(x) = (x-1)^3(x-4)^2(x+3)

Step-by-step explanation:

Zeros of a function:

Given a polynomial f(x), this polynomial has roots x_{1}, x_{2}, x_{n} such that it can be written as: a(x - x_{1})*(x - x_{2})*...*(x-x_n), in which a is the leading coefficient.

Zero 1 with multiplicity 3.

So

p(x) = (x-1)^3

Zero 4 with multiplicity 2.

Considering also the zero 1 with multiplicity 3.

p(x) = (x-1)^3(x-4)^2

Zero -3 with multiplicity 1:

Considering the previous zeros:

p(x) = (x-1)^3(x-4)^2(x-(-3)) = (x-1)^3(x-4)^2(x+3)

Degree is the multiplication of the multiplicities of the zeros. So

3*2*1 = 6

The 6th degree polynomial is p(x) = (x-1)^3(x-4)^2(x+3)

8 0
3 years ago
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