2x−1/4y=1 solve for y please

Mathematics

2 answers:

Elza [17]2 years ago

6 0

What the person above me said

Ivan2 years ago

3 0

Answer:

EASY DUBS:

Step-by-step explanation:

2*x-((1/4)*y) = 1 // - 1

2*x-((1/4)*y)-1 = 0

2*x+(-1/4)*y-1 = 0

2*x-1/4*y-1 = 0 // + -1/4*y-1

2*x = -(-1/4*y-1) // : 2

x = (-(-1/4*y-1))/2

x = (1-(-1/4*y))/2

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motikmotik

We have two points describing the diameter of a circumference, these are:

$\begin{gathered} A=(-12,-4) \\ B=(-4,-10) \end{gathered}$

Recall that the equation for the standard form of a circle is:

$(x-h)^2+(y-k)^2=r^2$

Where (h,k) is the coordinate of the center of the circle, to find this coordinate, we find the midpoint of the diameter, that is, the midpoint between points A and B.

For this we use the following equation:

$M=(\frac{x_1+x_2_{}_{}}{2},\frac{y_1+y_2}{2})$

Now, we replace and solve:

$\begin{gathered} M=(\frac{-12+(-4)}{2},\frac{-4+(-10)}{2} \\ M=(\frac{-12-4}{2},\frac{-4-10}{2}) \\ M=(\frac{-16}{2},\frac{-14}{2}) \\ M=(-8,-7) \end{gathered}$

The center of the circle is (-8,-7), so:

$\begin{gathered} h=-8 \\ k=-7 \end{gathered}$

On the other hand, we must find the radius of the circle, remember that the radius of a circle goes from the center of the circumference to a point on its arc, for this we use the following equation: