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AlekseyPX
3 years ago
14

What is the equation in point-slope form for the line parallel to y = 4x – 14 that contains P(–2, –6)?

Mathematics
2 answers:
lord [1]3 years ago
8 0
Point t slope form:
y + y value = m (x + x value) where m is the gradient
Parallel line must have the same gradient as the two lines never meet, so the gradient must be 4. This eliminates option B and D.
Remember that point-slope form is still an equation, so the values of both sides must be equal. So let's substitute the given coordinates.
Option A:
y-6=4(x+2)
-6-6 (-12) does not equal to 4(-2+2) (0)
Option C:
y+6=4(-2+2)
-6+6 (0) = 4(-2+2) (0)
Therefore, option C is your answer.
vesna_86 [32]3 years ago
7 0
- Point slope form is y - b = m(x - a), where m is the slope and (a, b) is a point on the line.
- Parallel lines have the same slope

The given equation is in slope-intercept form, which is y = mx + b, where m is the slope and b is the y-intercept. m in y = 4x - 14 is 4; our equation in point-slope form will have 4 as m.
We have the slope (4), so now we have to add the "point on the line" which is given: P(-2, -6). That's all the information needed to write an equation in point-slope form that's parallel to y = 4x - 14; all that's left is to substitute and simplify.

y - b = m(x - a)
y - (-6) = 4(x - (-2))
y + 6 = 4(x + 2)

Answer:
C. y + 6 = 4(x + 2)
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3 years ago
A plane is approaching an aircraft carrier at 25° angle of elevation from 3.2 miles away how far above sea level is the plane
s2008m [1.1K]

Answer:

Height\approx 1.35\ miles

Step-by-step explanation:

The angle of elevation=25\textdegree

It is 3.2\ miles away from the point.

If we imagine a right  triangle having an angle 25\textdegree.

Hypotenuse=3.2, Opposite=Height from sea level(h)

\sin 25=\frac{opposite}{hypotenuse}\\\\\sin 25=\frac{h}{3.2}\\\\h=3.2\times \sin 25\\\\h=3.2\times 0.4226\\\\h=1.3524\approx 1.35\ miles

8 0
3 years ago
Read 2 more answers
10. 10. If AB bisects CAF, and m&lt;EAF = 72°,<br>then the m&lt;BAF =​
never [62]

The measure of ∠BAF is 54°.

Solution:

DF and CE are intersecting lines.

m∠EAF = 72° and AB bisects ∠CAF.

∠EAF and ∠DAC are vertically opposite angles.

Vertical angle theorem:

<em>If two lines are intersecting, then vertically opposite angles are congruent.</em>

∠DAC ≅ ∠EAF

m∠DAC = 72°

<em>Sum of the adjacent angles in a straight line = 180°</em>

m∠DAE + m∠EAF = 180°

m∠DAE + 72° = 180°

Subtract 72° from both sides.

m∠DAE = 108°

∠CAF and ∠DAE are vertically opposite angles.

⇒ m∠CAF = m∠DAE

⇒ m∠CAF = 108°

AB bisects ∠CAF means ∠CAB = ∠BAF

m∠CAB + m∠BAF = 108°

m∠BAF + m∠BAF = 108°

2 m∠BAF = 108°

Divide by 2 on both sides, we get

m∠BAF = 54°

Hence the measure of ∠BAF is 54°.

4 0
3 years ago
Please please please can someone help me :)
disa [49]

Answer:

Step-by-step explanation:

now the equation looks like

3-4Cos(x)=y

hmmm i'm wondering if you can figure it out from here???  it's the same as the other two.. plug in that \sqrt{2} /2  .. can you?   :)

8 0
2 years ago
What is the prime factorization for 147
NemiM [27]
Prime Factorization = Divide by factors that are prime number

147 ÷  3 = 49
49 ÷ 7 = 7
7 ÷ 7 = 1
 
147 = 3 x 7 x 7

147 = 3 x 7²

-------------------------------------------------------------------------------
Answer: 147 = 3 x 7²
-------------------------------------------------------------------------------
4 0
3 years ago
Read 2 more answers
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