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dalvyx [7]
3 years ago
10

How many solutions are there to the equation below?

Mathematics
1 answer:
skad [1K]3 years ago
7 0

Answer:

A. Infinitely many

Step-by-step explanation:

9x + 27 = 9(x + 2) + 9

Distribute on the right side.

9x + 27 = 9x + 18 + 9

Combine like terms on the right side.

9x + 27 = 9x + 27

Subtract 27 from both sides.

9x = 9x

Divide both sides by 9.

x = x

x = x is a true statement for every value of x. Therefore, any value you substitute in for x will make the original equation true. That means there is a infinite number of solutions.

Answer: A. Infinitely many

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Find the measure of the line segment TR​
vredina [299]

9514 1404 393

Answer:

  24

Step-by-step explanation:

The product of lengths from the point where the secants meet to the near and far circle intersection points is the same for both secants.

  RQ·RC = RS·RT

  8(27) = (3x)(8x)

  9 = x^2 . . . . . . . . . divide by 24

  3 = x

Then the length of interest is ...

  TR = 8x = 8·3

  TR = 24

4 0
3 years ago
Technetium-99m is used as a radioactive tracer for certain medical tests. It has a half-life of 1 day. Consider the function T w
Alinara [238K]

Answer:

The expression that represents the number of days until only 10% remains is T((d) 10 %) =100×(\frac{1}{2} )^{3.322}.

Step-by-step explanation:

The equation for half life is of the form

A = A₀×(\frac{1}{2} )^{\frac{t}{h} }.........................................................................(1)

Where

A = Final amount

A₀ = Initial amount

t = Time

h = Half life

For the equation T(d) = 100×2⁽⁻²⁾....................................(2)

We have by comparison with the equation for half life

2 ≡ \frac{t}{h}  and and the equation (2) can be written as

Percentage remaining after 2 half lives is

\frac{A}{A_0} ×100=100×(\frac{1}{2} )^{2 }

However if the half life of Technetium-99m is 6 hours then we have for one day

\frac{A}{A_0} ×100=100×(\frac{1}{2} )^{2 *2}

Therefore an expression that represents the number of days until only 10% remains is

\frac{A}{A_0} ×100=100×(\frac{1}{2} )^{\frac{d}{h}  } = 10 %

(\frac{1}{2} )^{\frac{d}{h}  } =\frac{1}{10}

= ㏑(\frac{1}{2} )^{\frac{d}{h}  }  = ㏑(\frac{1}{10})

= \frac{d}{h}×㏑(\frac{1}{2} ) = ㏑(\frac{1}{10})

\frac{d}{h} = \frac{ln(\frac{1}{10}) }{ln(\frac{1}{2} )} = 3.322

Therefore the expression for the number of days 10 % of Technetium-99m will be remaining is

T((d) 10 %) =100×(\frac{1}{2} )^{3.322}

3 0
4 years ago
Determine whether each question is biased. explain your answer. 2.A beverage company conducts a survey in the lobby of a health
zheka24 [161]
2. a beverage company conducts a survey in the lobby of a health club to determine people's favorite beverage.

This question is biased, because certain drinks would be ruled out for being "unhealthy", such as soda, beer, etc. This means that healthier drinks, such as mineral water, electrolyte water, etc, would get more votes.


hope this helps
4 0
3 years ago
Tom gave a 10 bill for a 3.49 book how much change should he get back
Dovator [93]
6.51 that's the answer
7 0
4 years ago
Read 2 more answers
Cody has 4 cups of powdered sugar. He sprinkles 3/4 of the sugar onto a plate of brownies and sprinkles the rest onto a plate of
Mashcka [7]

Answer:

3 cups

Step-by-step explanation:

Assumptions: How much sugar does cost sprinkle on the brownies. Cost meant Cody

Given data:

Total of 4 cups

3/4 is sprinkled onto a plate of brownies

The rest onto a plate of lemon cookies

<em>Sugar sprinkled on brownies </em>= (3/4) * 4

<em>Sugar sprinkled on brownies</em> = 3 cups.

6 0
3 years ago
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