Answer:
Hello your question is incomplete below is the complete question
What is wrong with the equation? integral^2 _3 x^-3 dx = x^-2/-2]^2 _3 = -5/72 f(x) = x^-3 is continuous on the interval [-3, 2] so FTC2 cannot be applied. f(x) = x^-3 is not continuous on the interval [-3, 2] so FTC2 cannot be applied. f(x) = x^-3 is not continuous at x = -3, so FTC2 cannot be applied The lower limit is less than 0, so FTC2 cannot be applied. There is nothing wrong with the equation. If f(2) = 14, f' is continuous, and f'(x) dx = 15, what is the value of f(7)? F(7) =
answer : The value of f(7) = 29
Step-by-step explanation:
Attached below is the detailed solution
Hence : F(7) - 14 = 15
F(7) = 15 + 14 = 29
Product means the answer to multiplication problems.
so 7/2 = 3.5 then 3.5/2 = 1.75
(1.75 * 2) = 7/2
Two hours.
40%8=5 trees per hour. 50-40=10. 10% by 5=2.
Answer:

Step-by-step explanation:
<em>In order to calculate the slope m between two points (x1, y1) and (x2, y2), we can use the formula below:</em>
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<em>So, for points (4, 2) and (-16, -10), we have:</em>
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<em>Therefore, The Answer is </em>
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-4+-5=-9 because it's like adding but it has the negative sign