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3 years ago

11

One pound is equal to 16 ounces. The function O(p) takes a weight in pounds (as input) and returns a weight in ounces (as output

).
O(p) = 16p

What is the output of this function if the input is 4?

A.

12

B.

20

C.

4

D.

64

1 answer:

marshall27 [118]3 years ago

8 0

its not 4 i cant pass the class any more its 64

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Encuentre el radio y el área de círculos cuya circunferencias tienen las siguientes medidas

Vadim26 [7]

Answer:

Los radios de los círculos son $r_{1} \approx 9.995$ , $r_{2} \approx 2.013$ , $r_{3} \approx 7.592$ , respectivamente.

Las áreas de los círculos son $A_{1} \approx 313.845$ , $A_{2} \approx 12.730$ , $A_{3} \approx 181.077$ , respectivamente.

Step-by-step explanation:

La circunferencia ( $s$ ) se calcula mediante la siguiente fórmula:

$s = 2\pi\cdot r$ (1)

Donde $r$ es el radio del círculo.

Una vez hallado el radio, se determina el área de la figura geométrica ( $A$ ) mediante la siguiente fórmula:

$A = \pi\cdot r^{2}$ (2)

Si conocemos que las circunferencias son $s_{1} = 62.8$ , $s_{2} = 12.65$ y $s_{3} = 47.7$ , respectivamente:

1) Radios de los círculos

$r_{1} = \frac{s_{1}}{2\pi}$ , $r_{2} = \frac{s_{2}}{2\pi}$ , $r_{3} = \frac{s_{3}}{2\pi}$

$r_{1} \approx 9.995$ , $r_{2} \approx 2.013$ , $r_{3} \approx 7.592$

2) Áreas de los círculos

$A_{1} = \pi\cdot r_{1}^{2}$ , $A_{2} = \pi\cdot r_{2}^{2}$ , $A_{3} = \pi\cdot r_{3}^{2}$

$A_{1} \approx 313.845$ , $A_{2} \approx 12.730$ , $A_{3} \approx 181.077$

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Colleen recorded the type of trees in the woods near her house.She counted 20 trees and 50 maple trees.What is the experimental

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Answer: The required probability is $\dfrac{8}{125}$

Step-by-step explanation:

Since we have given that

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So, the probability would be :

$(\dfrac{20}{50})^3=(\dfrac{2}{5})^3=\dfrac{8}{125}$

Hence, the required probability is $\dfrac{8}{125}$

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igor_vitrenko [27]

Answer:

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Step-by-step explanation:

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