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jonny [76]
3 years ago
7

Lesson 4-3 Dividing Mixed Numbers Practice and Problem Solving: A/B

Mathematics
1 answer:
muminat3 years ago
3 0

Answer:

<h3>Reciprocals are: </h3>

1) 10 1/2 = 21/2

Reciprocal will be 2/21

2) 6 3/7 = 45/7

Reciprocal will be 7/45

3) 2 8/9 = 26/9

Reciprocal will be 9/26

4) 15 1/4 = 61/4

Reciprocal will be 4/61

5) 9 2/3 = 29/3

Reciprocal will be 3/29

6) 7 5/8 = 61/8

Reciprocal will be 8/61

<h3>Divide</h3>

7) 8/10 divide by 1 5/6

8/10 divide by 11/6

or 8/10 * 6/11

4/5* 6/11

24/55

8) 2 divides by 1 6/7

2 divides by 13/7

2 * 7/13

14/13

1 1/13

9) 3 3/5 divides by 2 1/4

18/5 divides by 9/4

18/5 * 4/9

8/5

1 3/5

10) 4 1/2 divides by 2 3/8

9/2 divides by 19/8

9/2 * 8/19

36/19

1 17/19

11) 5 5/6 divides by 3 1/6

35/6 divides by 19/6

35/6 * 6/19

35/19

1 16/19

12) 11/12 divides by 2 5/8

11/12 divides by 21/8

11/12 * 8/21

22/63

13) 1 9/13 divides by 3/8

22/13 divides by 3/8

22/13 * 8/3

176/39

4 20/39

14) 6 4/5 divides by 3 2/9

34/5 divides by 29/2

34/5 * 2/29

68/145

15) 9 2/3 divides by 6 8/9

29/3 divides by 62/9

87/62

1 25/69

<h3>Division problem</h3>

Width of patio = 5 2/3 feet

Area of patio = 36 5/6 sq. feet

Length will be: area /width

36 5/6 divides by 5 2/3

221/6 divides by 17/3

221/6 * 3/17

13/2

6 1/2 feet

Length is 6 1/2 feet, that means we can place the concrete patio on a 7 foot picnic table.

17) Area of mirror = 225 sq. inches

Width of mirror = 13 3/4 inches.

Length of mirror will be=area/ width

225 divides by 13 3/4

225 divides by 55/4

225 * 4/55

180/11

16 4/11

The width of mirror will be 16 4/11 feet. It is greater than 16 feet. Therefore mirror can't be fit in a space of 15 inches by 16 inches.

18) Total length of fabric = 16 1/5 yards

One fabric piece size= 5 2/5

Number of fabric pieces will be= total length/ 1 fabric length

16 1/5 divides by 5 2/5

81/5 divides by 27/5

81/5*5/27

3

There will be total 3 pieces of size 5 2/5 yards.

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According to a study done by Wakefield Research, the proportion of Americans who can order a meal in a foreign language is 0.47.
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Answer:

Probability that the proportion of Americans who can order a meal in a foreign language is greater than 0.5 is 0.19766.

Step-by-step explanation:

We are given that according to a study done by Wake field Research, the proportion of Americans who can order a meal in a foreign language is 0.47.

Suppose a random sample of 200 Americans is asked to disclose whether they can order a meal in a foreign language.

<em>Let </em>\hat p<em> = sample proportion of Americans who can order a meal in a foreign language</em>

The z-score probability distribution for sample proportion is given by;

          Z = \frac{ \hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion

p = population proportion of Americans who can order a meal in a foreign language = 0.47

n = sample of Americans = 200

Probability that the proportion of Americans who can order a meal in a foreign language is greater than 0.5 is given by = P( \hat p > 0.50)

  P( \hat p > 0.06) = P( \frac{ \hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } > \frac{0.5-0.47}{\sqrt{\frac{0.5(1-0.5)}{200} } } ) = P(Z > 0.85) = 1 - P(Z \leq 0.85)

                                                               = 1 - 0.80234 = <u>0.19766</u>

<em>Now, in the z table the P(Z  </em>\leq <em>x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 0.85 in the z table which has an area of 0.80234.</em>

Therefore, probability that the proportion of Americans who can order a meal in a foreign language is greater than 0.5 is 0.19766.

4 0
3 years ago
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