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Solnce55 [7]
3 years ago
9

Lines l and m are parallel. Parallel lines l and m are cut by transversals s and t. Clockwise from top left, the angles formed b

y s, t, and l are blank, 85 degrees, (2 x) degrees, (x minus 10) degrees, 1, blank; formed by s and m are blank, 2, blank, blank; formed by t and m are 3, blank, blank, blank. What is the measure of angle 3? 25 degrees 35 degrees 70 degrees 85 degrees

Mathematics
2 answers:
denis-greek [22]3 years ago
4 0

Answer:

25 degrees

Step-by-step explanation:

In the picture attached, the lines and the angles are shown. There we can see that:

85° + 2x° + (x-10)° = 180°

75 + 3x = 180

x = (180 - 75)/3

x = 35°

∠3 and ∠(x-10)° are alternate interior angles, therefore they are congruent, so:

∠3 = x - 10

∠3 = 35 - 10

∠3 = 25°

Alex787 [66]3 years ago
3 0

Answer:

a

Step-by-step explanation:

edge 2020

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(43 points) In the US, 85% of the population has Rh positive blood. Suppose we take a random sample of 6 persons and let Y denot
VladimirAG [237]

Answer:

a) Binomial distribution with parameters p=0.85 q=0.15 n=6

b) 62.29%

c) 2.38%

d) See explanation below

Step-by-step explanation:

a)

We could model this situation with a binomial distribution

P(6;k)=\binom{6}{k}p^kq^{6-k}

where P(6;k) is the probability of finding exactly k people out of 6 with Rh positive, p is the probability of finding one person with Rh positive and q=(1-p) the probability of finding a person with no Rh.

So

\bf P(Y=k)=\binom{6}{k}(0.85)^k(0.15)^{6-k}

b)  

The probability that Y is less than 6 is

P(Y=0)+P(Y=1)+...+P(Y=5)

Let's compute each of these terms

P(Y=0)=P(6;0)=\binom{6}{0}(0.85)^0(0.15)^{6}=1.139*10^{-5}

P(Y=1)=P(6;1)=\binom{6}{1}(0.85)^1(0.15)^{5}=0.0000387281

P(Y=2)=P(6;2)=\binom{6}{2}(0.85)^2(0.15)^{4}=0.005486484

P(Y=3)=P(6;3)=\binom{6}{3}(0.85)^3(0.15)^{3}=0.041453438

P(Y=4)=P(6;4)=\binom{6}{4}(0.85)^4(0.15)^{2}=0.176177109

P(Y=5)=P(6;5)=\binom{6}{5}(0.85)^5(0.15)^{1}=0.399334781

and adding up these values we have that the probability that Y is less than 6 is

\sum_{i=1}^{5}P(Y=i)=0.622850484\approx 0.6229=62.29\%

c)

In this case is a binomial distribution with n=200 instead of 6.

p and q remain the same.

The mean of this sample would be 85% of 200 = 170.  

In a binomial distribution, the standard deviation is  

s = \sqrt{npq}

In this case  

\sqrt{200(0.85)(0.15)}=5.05

<em>Let's approximate the distribution with a normal distribution with mean 170 and standard deviation 5.05</em>

So, the approximate probability that there are fewer than 160 persons with Rh positive blood in a sample of 200 would be the area under the normal curve to the left of 160

(see picture attached)

We can compute that area with a computer and find it is  

0.0238 or 2.38%

d)<em> In order to approximate a binomial distribution with a normal distribution we need a large sample like the one taken in c).</em>

In general, we can do this if the sample of size n the following inequalities hold:

np\geq 5 \;and\;nq \geq 5

in our case np = 200*0.85 = 170 and nq = 200*0.15 = 30

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Answer:

her balance aka ADB would be 372.08

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Answer:

5/6 and 7/9

Step-by-step explanation:

A and D are less than 2/3 so B and C is correct.

Hope this helps plz mark brainliest :D

6 0
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