All categories

3 years ago

Identify the graphed linear equation.

Mathematics

2 answers:

Lubov Fominskaja [6]3 years ago

6 0

The answer would be c

Sergio039 [100]3 years ago

5 0

y = - 4x + 1 → C

the equation of the line in ' slope-intercept form ' is

y = mx + c ( m is the slope and c the y-intercept )

from the graph c = 1

using the points ( 0 , 1 ) and (1 , - 3 )

m = (- 3 - 1 )/( 1 - 0) = (- 4 )/1 = -4

equation is y = - 4x + 1

You might be interested in

Find the value of x for the question shown above

Sindrei [870]

hint; the sum of all angles in a triangle is 180° !

^so all together it’s gonna be 180 !

hope this helped !

i’m pretty sure the value of it (x) is 12 but am not sure

8 0

2 years ago

HELP......................................

djyliett [7]

Answer:

The equation's result: 32,000 (Rounded)

Goal: Find the closest or equivalent result in another expression

Step-by-step explanation:

$(1.5^{15})/(0.7^{12})\\(1.5^{15})/(0.7^{12}) = (437.894)/(0.7^{12})\\437.894/(0.014)\\31636.79$

How we got to 31,636 was by dividing from left to right.

Remember: When dividing decimals, it's like multiplying whole numbers in a way. The number(the quotient, also) ends up bigger instead of being smaller like when dividing whole numbers. If you multiply decimals, they(the product) end up smaller.

Therefore, A is the correct answer.

4 0

9 months ago

Yan has already finished 3/5 of the 45 math problems he was assigned today. Each math problem took him 1 4/5 of a minute to comp

kobusy [5.1K]

Answer:

He will finish the rest of the problems in 32.4 minutes.

Step-by-step explanation:

Since we are given that Yan has completed 3/5 of 45 problems i.e.

$\frac{3}{5}*45$

$27$

Thus he has completed 27 problems

Remaining no. of problems are 45-27 = 18

Since he complete each problem in minutes = $1\frac{4}{5} =\frac{9}{5} =1.8$

So, he completes 18 problems in minutes = 18 *1.8 = 32.4 minutes

Hence , He will finish the rest of the problems in 32.4 minutes.

3 0

2 years ago

At Munder Difflin Paper Company, the manager Mitchell Short randomly places golden sheets of paper inside of 30% of their paper

Korvikt [17]

Answer:

90.67% probability that John finds less than 7 golden sheets of paper

Step-by-step explanation:

For each container, there are only two possible outcomes. Either it contains a golden sheet of paper, or it does not. The probability of a container containing a golden sheet of paper is independent of other containers. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

At Munder Difflin Paper Company, the manager Mitchell Short randomly places golden sheets of paper inside of 30% of their paper containers.

This means that $p = 0.3$

14 of these containers of paper.

This means that $n = 14$

What is the probability that John finds less than 7 golden sheets of paper?

$P(X < 7) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{14,0}.(0.3)^{0}.(0.7)^{14} = 0.0068$

$P(X = 1) = C_{14,1}.(0.3)^{1}.(0.7)^{13} = 0.0407$

$P(X = 2) = C_{14,2}.(0.3)^{2}.(0.7)^{12} = 0.1134$

$P(X = 3) = C_{14,3}.(0.3)^{3}.(0.7)^{11} = 0.1943$

$P(X = 4) = C_{14,4}.(0.3)^{4}.(0.7)^{10} = 0.2290$

$P(X = 5) = C_{14,5}.(0.3)^{5}.(0.7)^{9} = 0.1963$

$P(X = 6) = C_{14,6}.(0.3)^{6}.(0.7)^{8} = 0.1262$

$P(X < 7) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) = 0.0068 + 0.0407 + 0.1134 + 0.1943 + 0.2290 + 0.1963 + 0.1262 = 0.9067$

90.67% probability that John finds less than 7 golden sheets of paper

7 0

2 years ago

An alloy of silver and gold is to be recast with an addition of silver. This new alloy consists of 80 ounces and is to have only

Liula [17]

Answer:

What percentage of gold is in the new alloy after the recasting? 4

Step-by-step explanation:

(80/5)*(1/5)/80=0.04

5 0

3 years ago