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Mrrafil [7]
4 years ago
9

Identify the graphed linear equation.

Mathematics
2 answers:
Lubov Fominskaja [6]4 years ago
6 0
The answer would be c
Sergio039 [100]4 years ago
5 0

y = - 4x + 1 → C

the equation of the line in ' slope-intercept form ' is

y = mx + c ( m is the slope and c the y-intercept )

from the graph c = 1

using the points ( 0 , 1 ) and (1 , - 3 )

m = (- 3 - 1 )/( 1 - 0) = (- 4 )/1 = -4

equation is y = - 4x + 1


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Two buildings are facing each other on a road of width 12 metre . From the top of the first building, which is 10 metre high , t
Karo-lina-s [1.5K]

Answer:

\displaystyle 10 + 12\sqrt{3} <em>metres</em>

Step-by-step explanation:

You are finding the <em>height</em><em> </em>of the building with an angle of elevation, therefore we need to solve for <em>EC</em><em> </em>to add it to <em>BA</em><em> </em>[10 metres] and use TRIGONOMETRIC RATIOS to arrive at our conclusion. Just in case you have forgotten what they were, here they are:

\displaystyle \frac{OPPOSITE}{HYPOTENUSE} = sin\:θ \\ \frac{ADJACENT}{HYPOTENUSE} = cos\:θ \\ \frac{OPPOSITE}{ADJACENT} = tan\:θ \\ \frac{HYPOTENUSE}{ADJACENT} = sec\:θ \\ \frac{HYPOTENUSE}{OPPOSITE} = csc\:θ \\ \frac{ADJACENT}{OPPOSITE} = cot\:θ

We can now solve for <em>EC</em>:

\displaystyle cot\:60 = \frac{12}{EC} → ECcot\:60 = 12 \\ \\ \frac{ECcot\:60}{cot\:60} = \frac{12}{cot\:60} → 12\sqrt{3} = EC

<em>OR</em>

\displaystyle tan\:60 = \frac{EC}{12} → 12tan\:60 = EC → 12\sqrt{3} = EC

Now that you have solved for <em>EC</em>, you can now add it to your original 10 metres to get \displaystyle 10 + 12\sqrt{3} <em>metres</em>. As a decimal, you would get \displaystyle 30,78460969... <em>metres</em>. You can go ahead and round this off if necessary.

** The reason why the <em>cotangent</em><em> </em>[or <em>tangent</em>] ratio was used was because <em>EA</em><em> </em>is equivalent to <em>DB</em> by the definition of a rectangle. It has two pairs of parallel and congruent sides with <em>four</em><em> </em><em>right</em><em> </em><em>angles</em>. Plus, that is the <em>adjacent</em><em> </em><em>side</em><em> </em>of the triangle, while <em>EC</em><em> </em>is the <em>opposite</em><em> </em><em>side</em><em> </em>of the triangle, so we knew our ratios were correct.

I am joyous to assist you at any time.

8 0
3 years ago
$9.75 to $11.50= what percent change? Round to the earth tenth of a <br> percent
Firdavs [7]

Answer:17.9 percent  

6 0
3 years ago
Two lines and a transversal form corresponding angles that are congruent. Describe the two lines
antoniya [11.8K]

Answer:

parallel

Step-by-step explanation:

If you have two lines and a transversal that form corresponding angles that are congruent. Then the alternate interior angles are congruent and the same-side interior (some people call these consecutive angles) are supplementary.

This has to deal with Parallel Lines Theorem or the Converse of Parallel Lines Theorem.

The lines would be parallel.

8 0
3 years ago
130 is 65% of what number?
mina [271]
X - the number

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130 is 65% of 200.
4 0
4 years ago
A car and a truck are traveling north on a highway. The truck has a speed of 42 mph and the car has a speed of 37 mph. If the tr
irga5000 [103]

Answer:

  5 mph north

Step-by-step explanation:

The relative velocity of the truck with respect to the car is ...

  relative velocity = truck velocity - car velocity

  relative velocity = 42 mph north - 37 mph north

  relative velocity = 5 mph north

5 0
4 years ago
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