The quotient of 6x^3+2x^2−x and x is 6x^3+2x^2−x divided by x
The value of the quotient 6x^3+2x^2−x by x is 6x^2 + 2x - 1
<h3>How to determine the quotient</h3>
The quotient expression is given as:
6x^3+2x^2−x divide by x
The above means that,
We divide 6x^2 by x, we divide 2x^2 by x and we divide -x by x.
So, we have:
6x^3+2x^2−x divide by x = 6x^2 + 2x - 1
Hence, the value of the quotient 6x^3+2x^2−x is 6x^2 + 2x - 1
Read more about quotient at:
brainly.com/question/7068223
Answer:
4 4/1
Step-by-step explanation:
we know that reciprocal mans backwards. This doesn't apply to the whole number un math. only the denominational and numerator.
8.9 I think...not sure tho
