Answer:
x= -3 is the answer
UW=3 is the answer..
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Answer:
1857.12 square meters
Step-by-step explanation:
Let L be the length of the rectangle and 'W' be the width
Perimeter = 
The fencing material costs $30 per meter.
The material for the partitions costs $25 per meter


Solve for L

Area = length times width

Now take derivative and set it =0

set the derivative =0 and solve for W

So width = 31.8 that gives maximum area

square meter
Answer:15/16 > 1/2
Step-by-step explanation:
Answer:
It would be (1,-1)
Step-by-step explanation: