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yan [13]
3 years ago
10

I forgot how to do this ?I need help in interest please help

Mathematics
1 answer:
salantis [7]3 years ago
6 0
I=prt so you multiply principal rate and time to get the answer
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If f and g are functions of time, and at time t = 3, f equals 8 and is rising at a rate of 2 units per second, and g equals 3 an
Sidana [21]
It gives you a few values. The values of f(t) and g(t) when time t=3,  and
the values of the rates of change (first derivative) for both at the same time t=3.

f(3) = 8  unit
f ' (3) = 2  unit/s
g(3) = 3  unit
g ' (3) = 8 unit/s

--and also a value of the ratio of the two functions at t=3
 \frac{f(3)}{g(3)} = \frac{8}{3}
7 0
4 years ago
He how do you do this
OlgaM077 [116]

Answer:

I'm not sure. have you tried googling? Also where is comments on this site I'm kinda new

Step-by-step explanation:

4 0
3 years ago
Y Given: 6x + 7 = 8x - 17; Prove: x = 12
Molodets [167]

REASONS:-

1ST STEP

6x + 7 = 8x - 17

GIVEN LHS = RHS

2ND STEP

7 = 2x - 17

Bez +ve 6x when move to another side will change to -ve so it reduces 8x to 2x

3RD STEP

24 = 2x

Bez -ve 17 when move to another side will change to +ve so it increases 7 to 24

4TH STEP

12 = x

Bez 2 in multiplication when move to another side will change to division so it reduces 24 to 12

5TH STEP

x = 12

it the answer we obtained after solving

6 0
3 years ago
In the equation y=a(x-h)^2+k, the "k" translates the parabola in what manner?
stellarik [79]

Answer:

k is the vertical shift

Step-by-step explanation:

y=a(x-h)^2+k

This gives the parabola in vertex form

(h,k) is the vertex where h is the x coordinate and k is the y coordinate

k is the vertical shift

4 0
3 years ago
Find the area of the region bounded by the y-axis, the line y=6, and the line y = 1/2.
Ghella [55]

Solution:

As region bounded by y-axis, the line y=6, and the line y=1/2 is a line segment of definite length on y-axis.

We consider a line , one dimensional  if it's thickness is negligible.

So, Line is  two dimensional if it's thickness is not negligible becomes a quadrilateral.

So, Area (region bounded by y-axis, the line y=6, and the line y=1/2 is a line segment of definite length on y-axis)= Area of line segment between [,y=6 and  y=1/2.]= 6-1/2=11/2 units if we consider thickness of line as negligible.

4 0
3 years ago
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