The sums range from 2 to 12 of which 6 are even out of 11 possible sums.
There are 4 multiples of 3, two of which are odd.
So the number of even sums is 6 and there are 2 unique or odd multiples of 3.
So there are a total 6+2=8 outcomes we want out of 36 possible outcomes.
The probability is then 8/36 or 2/9
Arrange the data values in order from least to greatest. 4,3,6,10,3,14,8,5,7,11,7,8
DedPeter [7]
3,3,4,5,6,7,7,8,8,10,11,14