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Anastasy [175]
3 years ago
14

Keisha went into a park at 1:30 pm she hiked for 1 hour 35 minutes. Then she went to the picnic area for 45 minutes and left the

park. What time did keisha leave the park?
Mathematics
1 answer:
nata0808 [166]3 years ago
3 0

Answer:

3:50pm

Time Keisha went to the park- 1:30pm

Time spent for hiking- 1hour 35 minutes

Time spent at the picnic area- 45 minutes

1: 30pm

<u>+1. 35mi</u>n

<u> 2: 65pm</u>

But 60 minutes is 1 hour so the 65 will be changed to 1 hour 5 minutes making it

3: 05pm

3: 05pm

<u>+0: 45min</u>

<u> 3: 50pm</u>

Hence the time Keisha left the park was 3:50pm

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The answer is

<h2>2 \sqrt{2 }  \:  \: or \:  \: 2.828 \:  \:  \: units</h2>

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<h3>d =  \sqrt{ ({x1 - x2})^{2}  +  ({y1 - y2})^{2} }  \\</h3>

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From the question the points are

E(-3,4) and B(-1,6)

The distance between them is

<h3>|EB|  =  \sqrt{ ({ - 3 + 1})^{2} +  ({4 - 6})^{2}  }  \\  =  \sqrt{ ({ - 2})^{2}  +  ({ - 2})^{2} }  \\  =  \sqrt{4 + 4}  \ \   \\  = \sqrt{8}</h3>

We have the final answer as

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