All categories

3 years ago

Is my answer correct? // tell me if i'm wrong with details!!

Mathematics

1 answer:

Anna11 [10]3 years ago

5 0

Answer:

Step-by-step explanation:

This is vertical reflection, because reflections are made across vertical lines.

You might be interested in

In a set of real numbers, the first number less then -3 is -4 true or false

Annette [7]

Answer:

true

Step-by-step explanation:

the bigger the number of a negative integer, the smaller the value become

8 0

3 years ago

Read 2 more answers

What is 0.1 as a fraction

Inga [223]

Answer:

1/10

Step-by-step explanation:

8 0

2 years ago

There are 16 students playing kickball. Two students leave to go play hopscotch. How do you write the fraction of children left

olga55 [171]

Answer:

7/8

Step-by-step explanation:

When 16 students are playing kickball, there are 16/16 students on the field. After 2 leave, this becomes 16-2/16, therefore 14/16 which is divisible by 2. and therefore 7/8, which the numerator and denominator have no common divisors.

6 0

3 years ago

The functions r and s are defined as follows. r(x)=-x-5 s(x)= -2x-5 . Find the value of s(r(4)).

Svet_ta [14]

Answer:

s(r(4)) = 13

Step-by-step explanation:

Substitute and calculate:

s(r(4)) = 13

6 0

2 years ago

In a certain Algebra 2 class of 30 students, 19 of them play basketball and 12 of them play baseball. There are 8 students who p

Alenkinab [10]

Answer:

Probability that a student chosen randomly from the class plays basketball or baseball is $\frac{23}{30}$ or 0.76

Step-by-step explanation:

Given:

Total number of students in the class = 30

Number of students who plays basket ball = 19

Number of students who plays base ball = 12

Number of students who plays base both the games = 8

To find:

Probability that a student chosen randomly from the class plays basketball or baseball=?

Solution:

$P(A \cup B)=P(A)+P(B)-P(A \cap B)$ ---------------(1)

where

P(A) = Probability of choosing a student playing basket ball

P(B) = Probability of choosing a student playing base ball

P(A \cap B) = Probability of choosing a student playing both the games

Finding P(A)

P(A) = $\frac{\text { Number of students playing basket ball }}{\text{Total number of students}}$

P(A) = $\frac{19}{30}$ --------------------------(2)

Finding P(B)

P(B) = $\frac{\text { Number of students playing baseball }}{\text{Total number of students}}$

P(B) = $\frac{12}{30}$ ---------------------------(3)

Finding $P(A \cap B)$

P(A) = $\frac{\text { Number of students playing both games }}{\text{Total number of students}}$

P(A) = $\frac{8}{30}$ -----------------------------(4)

Now substituting (2), (3) , (4) in (1), we get

$P(A \cup B)= \frac{19}{30} + \frac{12}{30} -\frac{8}{30}$

$P(A \cup B)= \frac{31}{30} -\frac{8}{30}$

$P(A \cup B)= \frac{23}{30}$

7 0

3 years ago