The common ratio in a geometric series is 4 and the first term is 3 Find the sum of the first 8 terms in the series.
1 answer:
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Answer:
Step-by-step explanation:
a.
y=0.75x
y-y1=(y2-y1)/(x2-x1)×(x-x1)
y-3=(6-3)/(8-4) (x-4)
y-3=3/4(x-4)
y-3=3/4 x-3
y=3/4 x-3+3
y=3/4 x
if y=f(x)
f(x)=0.75x
c.
f(12)=0.75×12=9$
