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3 years ago

Simplifly the expression 5^0

1 answer:

3 0

ANY number raised to the zero power is ' 1 '.

(This rule is worth memorizing. You'll amaze all of
your friends, especially the ones who don't know
how to do it without running to Google.)

So 5^0 = 1 .

You might be interested in

The area of a rectangle is 42 ft squared, and the length of the rectangle is 5 ft more than twice the width. Find the dimensions

stira [4]

Answer:

<h3>Length = 12 ft</h3>

Width = $\frac{7}{2} ft$

Step-by-step explanation:

Given,

Area of rectangle = $42 \: {ft}^{2}$

Width = X

Length = 2x + 5

Now,

$x(2x + 5) = 42$

$2 {x}^{2} + 5x = 42$

$2 {x}^{2} + 5x - 42 = 0$

$2 {x}^{2} + 12x - 7x - 42 = 0$

$2x(x + 6) - 7(x + 6) = 0$

$(2x - 7)(x + 6) = 0$

Either

$2x - 7 = 0$

$2x = 0 + 7$

$2x = 7$

$x = \frac{7}{2}$

Or,

$x + 6 = 0$

$x = 0 - 6$

$x = - 6$

Negative value can't be taken.

So, width = $\frac{7}{2} ft$

Again,

Finding the value of length,

Length = $2x + 5$

$2 \times \frac{7}{2} + 5$

$7 + 5$

$12$

Length = 12 ft

7 0

3 years ago

Read 2 more answers

the diameter of a piston for an automobile is 3 11/16in with tolerence of 1/64in. find the upper and lower limits of the pistons

padilas [110]

Upper Tolerance

Remark

The 11/16 is the only thing that will be affected. The three won't go up or down when we add 1/64 so we should just work with the 11/16. We need only add 11/16 and 1/64 together to see what the upper range is. Later on we can add 3 into the mix.

Solution

<u>Upper Limit</u>

$\dfrac{11}{16} + \dfrac{1}{64}$

Now change the 11/16 into 64. Multiply numerator and denominator or 11/16 by 4

$\dfrac{11*4}{16*4} + \dfrac{1}{64}$

$\dfrac{11*4}{16*4} + \dfrac{1}{64}$ Which results in

$\dfrac{44}{64} + \dfrac{1}{64}$

With a final result for the fractions of 45/64

So the upper tolerance = 3 45/64

<u>Lower Tolerance</u>

Just follow the same steps as you did for the upper tolerance except you subtract 1/64 like this.

$\dfrac{11}{16} - \dfrac{1}{64}$

Your answer should be 3 and 43/64

4 0

3 years ago

The chess club members bought tickets to a tournament for $15. how much would they have paid if all 9 members went? pls explain

nydimaria [60]

Answer:

9 X 15 = $135

Step-by-step explanation:

Multiply the equation.

5 0

3 years ago

The floor of a round hut has a diameter of 6 meters. What is the floor's area? Use 3.14 for pi.

storchak [24]

Area is 28.26 meters

3 0

3 years ago

A rectangular solid with a square base has a volume of 4096 cubic inches - determine the dimensions that yield the minimum surfa

Bumek [7]

Answer:

side of base, a = 10.1 inches, height, h = 40.1 inches

Step-by-step explanation:

Volume of rectangular solid, V = 4096 cubic inches

Let the side of base is a and the height is h.

$V = a^2h\\\\4096 = a^2 h ..... (1)$

surface area of the solid

$S = 2a^2 + 4 ah \\\\S = 2a^2 + 4 \times a \times \frac{4096}{a^2} from (1)\\\S = 2a^2 + \frac{4096}{a}\\\\\frac{dS}{da}= 4 a - \frac{4096}{a^2}\\\\4 a - \frac{4096}{a^2} = 0 \\\\a^3 = 1024\\\\a =10.1 inches$

So, h = 40.2 inches

5 0

3 years ago